Consider the reaction C12H22O11(s)+12O2(g)→12CO2(g)+11H2O(l) in which 10.0 g of sucrose, C12H22O11, was burned in a bomb calorimeter with a heat capacity of 7.50 kJ/∘C. The temperature increase inside the calorimeter was found to be 22.0 ∘C. Calculate the change in internal energy, ΔE, for this reaction per mole of sucrose.
Answers
Answer:
the change in internal energy per mole of sucrose is 5989 KJ/mol
Explanation:
Since the calorimeter is a bomb calorimeter , where the volume remains constant
ΔE= Qrx
And assuming no heat losses to the surroundings
Qv + Qrx = 0
Cc*ΔT - Qrx = 0 ,
Qrx = Cc * ΔT = 7.50 KJ/°C * 22 °C = 165 KJ
the change in internal energy is calculated dividing by the number of sucrose moles involved n. the molecular weight of sucrose is
Mw= 12* 12g/mol + 22* 1g/mol + 11* 16 g/mol = 342 g/mol
n = m / Mw = 10 g / 342 g/mol = 0.029 mol
the change in internal energy per mole of sucrose is
Δe= ΔE/n = 165 KJ/0.029 mol = 5989 KJ/mol
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Answers
Explanation:
A solution consists of two type of substances. These are solute and solvent.
A solvent is defined as the substance present in lesser amount as compared to a solvent. A solute is able to dissolve in a solvent.
For example, sugar dissolves in water. Here, sugar is the solute and water is the solvent.
Combination of both solute and solvent results in the formation of a solution.
Whereas a solvent is a substance that is present in more quantity as compared to a solute.
Thus, we can conclude that the component which dissolves in a solution is called the solute.
B. lower than 7 is considered basic.
C. higher than 7 is considered an acid.
D. of 6 is considered neutral.
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Answer:
close to 14 is considered a strong base.
Explanation:
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Answers
Answer:
Moles of Carbon in the product = 0.183 mol
Explanation:
Complete combustion of an organic compound in the presence of excess oxygen will give carbon dioxide (CO2) and water vapour(H2O).
Equation of reaction
CxHyOz(s) + (2x + y/2 - z)/2 O2(g) --> x CO2(g) + y/2 H2O(l)
Moles of products
CO2
Molar mass of CO2 = 12 + (16*2)
= 44 g/mol
n(CO2) = 8.07/44.0
= 0.183 mol
One compound of CO2 has 1 Carbon atom and 2 Oxygen atom.
So if we have,
0.183 moles of carbon dioxide then
0.183 moles of carbon.
The mass of carbon in the product, m = 0.183*12
= 2.20 g
H2O:
Molar mass of H2O = (1*2) + 16
= 18 g/mol
Number of moles of H2O =
= 3.3/18
= 0.183 mol
One compound of H2O has 2 Hydrogen atom and 1 Oxygen atom.
0.183 moles of water then we also have
= 2*(0.183)
= 0.367 moles of hydrogen in the sample.
The mass of hydrogen in the compound, m
= 0.367*1
= 0.367 g
Adding these two values together will give us the mass of our compound that C and H;
2.2 + 0.367
= 2.567 g
So for the Oxygen,
5.5 g - 2.567
= 2.933 g
Moles of Oxygen;
Molar mass of O = 16 g/mol
= 2.933/16
= 0.183 mol
There are 0.030 moles of carbon in the original sample as per the mole concept.
Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.
It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.
It is given by the formula,
The given values are,mass=
molar mass=
Substitution of values in formula gives,
Thus, there are 0.030 moles of carbon in the original sample as per the mole concept.
Learn more about mole concept,here:
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Answers
I hope this helps and if anything is unclear feel free to ask about it in the comments.
a. As the temperature decreases, the molecules gain energy and move closer together, causing the balloon to shrink.
b.As the balloon releases energy, the molecules break apart into atoms, causing the balloon to shrink.
c.As the temperature decreases, the molecules lose energy and move closer together, causing the balloon to shrink.
d.As the balloon absorbs energy, the molecules move more quickly, causing the balloon to shrink.