is required?
a. 7.00 mL
b. 8.40 mL
c. 17.1 mL
d. 58.3 mL
Answer:
Explanation:
To determine the volume of the stock solution required to prepare 3.50 L of 0.200 M hydro chloric acid, we can use the formula:
M1V1 = M2V2
where:
M1 = concentration of the stock solution
V1 = volume of the stock solution
M2 = desired concentration of the diluted solution
V2 = desired volume of the diluted solution
Let's substitute the given values into the formula:
M1 = 12.0 M
V1 = ?
M2 = 0.200 M
V2 = 3.50 L
Now we can solve for V1:
12.0 M x V1 = 0.200 M x 3.50 L
V1 = (0.200 M x 3.50 L) / 12.0 M
V1 = 0.0583 L
To convert the volume from liters to milliliters, we multiply by 1000:
V1 = 0.0583 L x 1000 mL/L
V1 = 58.3 mL
Therefore, the volume of the stock solution required is 58.3 mL.
So, the correct answer is d. 58.3 mL.
To determine the volume of the stock solution required, we can use the formula:
Molarity1 x Volume1 = Molarity2 x Volume2
Where Molarity1 and Volume1 represent the initial concentration and volume, and Molarity2 and Volume2 represent the final concentration and volume.
Given:
Molarity1 = 12.0 M
Volume1 = ?
Molarity2 = 0.200 M
Volume2 = 3.50 L
Plugging in the values into the formula, we have:
12.0 M x Volume1 = 0.200 M x 3.50 L
Simplifying the equation, we can solve for Volume1:
Volume1 = (0.200 M x 3.50 L) / 12.0 M
Volume1 ≈ 0.0583 L
To convert this to milliliters, we multiply by 1000:
Volume1 ≈ 58.3 mL
Therefore, the volume of the stock solution required is approximately 58.3 mL.
The closest answer option is d. 58.3 mL.
I hope this explanation helps! Let me know if you have any further questions.
The is Answer is air
It is located in deep sea regions.
b.
It supports few species.
c.
It is a large and complex organism.
d.
It is composed of thousands of individuals.
I know for a fact that the answer to this question is d; i just took the test & got it right. It's also the most logical response. Hope i helped!
Answer:
group # = # valence electrons
group 2= 2 valence electrons
Explanation:
Mg is in group #2 and subsequently has 2 valence electrons (electrons on the outermost shell)
Answer:
5 pumpkin pies could be made with 7.5 cups of sugar.
Explanation:
The conversion factor to solve the problem is: