A force of 1500 pounds drags a truck 40 feet in 20 seconds. How much work is accomplished? How much power was required?

Answers

Answer 1
Answer:

Answer:

The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Explanation:

Given that,

Force F = 1500 pounds

Distance d = 40 feet

Time t = 40 sec

Work done :

The work done is the product of the force and distance.

The work done is defined as,

W = F * d

Where, W = work

F = force

d = distance

Put the value into the formula of work

W= 1500*40

W = 60000\ Pounds-feet

Power:

The power is equal to the work done divided by time.

The power is defined as,

P = (W)/(t)

Where, P = power

W = work

t = time

Put the value into the formula of power

P = (60000)/(20)

P=3000\ Pounds-feet/s

Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Answer 2
Answer: work = f x s = 1500 x 40
power = w/t = (1500 x 40) / 20

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You decide to go on a walk around the school. Starting from the student parking lot you move 25 m North and then 50 m West to reach a road. What is the total distance and displacement traveled on your brief trek?Distance:
Displacement:

Answers

Distance: The total distance traveled is the sum of the individual distances traveled in each direction. In this case, you moved 25 meters North and then 50 meters West. So, the total distance is:

Distance = 25 m (North) + 50 m (West) = 75 meters

Displacement: Displacement is the straight-line distance from the starting point to the final point, taking into account both the distance and direction. To calculate the displacement, you can use the Pythagorean theorem because the motion is in perpendicular directions (North and West).

Displacement = √((25 m)² + (50 m)²)

Displacement = √(625 m² + 2500 m²)

Displacement = √(3125 m²)

Displacement = 55.9 meters (rounded to one decimal place)

-the total displacement is approximately 55.9 meters in a direction that is between North and West.

What is the apparent magnitude of the brightest star in the Big Dipper?

Answers

Answer: +1.77

Explanation:

Big dipper is the  asterism made of seven bright stars in Ursa Major constellation. An asterism a pattern formed by joining the bright stars in the night sky. On the other hand, whole night sky is divided into 88 areas called constellations. These asterisms are used to identify the constellations.

The brightest star of the big dipper is Alioth which is the 32nd brightest star in the night sky. Its apparent magnitude is +1.77.

The magnitude of Alioth ( the brightest star in the big dipper ) is 1.76 and it is about 81 light years distant from Earth. 

The voltage, V (in volts), across a circuit is given by Ohm's law: V=IR, where I is the current (in amps) flowing through the circuit and R is the resistance (in ohms). If we place two circuits, with resistance R1 and R2, in parallel, then their combined resistance, R, is given by 1R=1R1+1R2. Suppose the current is 3 amps and increasing at 0.02 amps/sec and R1 is 4 ohms and increasing at 0.4 ohms/sec, while R2 is 3 ohms and decreasing at 0.2 ohms/sec. Calculate the rate at which the voltage is changing.

Answers

The rate at which the voltage of the given circuit is changing is gotten to be;

dV/dt = 0.452 V/s

We are given;

Current; I = 3 A

Resistance 1; R1 = 4Ω

Resistance 2; R2 = 3Ω

dR1/dt = 0.4 Ω/s

dR2/dt = 0.2 Ω/s

dI/dt = 0.02 A/s

Now, formula for voltage with resistors in parallel is;

1/V = (1/I)(1/R1 + 1/R2)

Plugging in the relevant values, we can find V;

1/V = (1/3)(1/4 + 1/3)

Simplifying this gives;

1/V = 0.194

Now, we want to find the rate at which the voltage is charging, we need to find dV/dt.

Thus, let us differentiate 1/V = (1/I)(1/R1 + 1/R2) with respect to t to get;

(1/V)²(dV/dt) = [(1/i²)(di/dt)(1/R1 + 1/R2)] + (1/I)[(1/R1²)(dR1/dt) + (1/R2²)(dR2/dt)]

Plugging in the relevant vies gives us;

0.194²(dV/dt) = [(1/3²)(0.02)(¼ + ⅓)] + (⅓)[(1/3²)(0.4) + (1/4²)(0.3)]

>> 0.037636(dV/dt) = 0.001296 + 0.0157

>> dV/dt = 0.016996/0.037636

>> dV/dt = 0.452 V/s

Read more at; brainly.com/question/13539417

Answer:

(dV)/(dt) = 0.453 Volts/s

Explanation:

As we know that two resistors are in parallel

so we have

V = i R

where we know that

(1)/(R) = (1)/(R_1) + (1)/(R_2)

so we have

(1)/(V) = (1)/(i)((1)/(R_1) + (1)/(R_2))

now to find the rate of change we have

(1)/(V^2)(dV)/(dt) = (1)/(i^2)(di)/(dt)((1)/(R_1) + (1)/(R_2)) + (1)/(i)((1)/(R_1^2)((dR_1)/(dt)) + (1)/(R_2^2)((dR_2)/(dt)))

(1)/(V) = (1)/(3)((1)/(4) + (1)/(3))

(1)/(V) = 0.194

now from above equation we have

(0.194)^2(dV)/(dt) = (1)/(3^2)(0.02)((1)/(4) + (1)/(3)) + (1)/(3)((1)/(4^2)(0.4) + (1)/(3^2)(0.2))

0.0376(dV)/(dt) = 1.296* 10^(-3) + 0.0157

(dV)/(dt) = 0.453 Volts/s

A gas occupies a volume of 20 cubic meters at 9,000 pascals. If the pressure is lowered to 5,000 pascals, what volume will the gas occupy?

Answers

We need to consider no change in the temperature of gas (isothermal transformation)

Volume and pressure are inversely proportional magnitudes, so we can write:

P_1.V_1=P_2.V_2\n \n 9.20=5.V_2\n \n V_2=(180)/(5)=36 \ m^3

All solid objects above 0 Kelvin emit energy.
a. True
b. False

Answers

Answer: true

Explanation: The zero Kelvin is the point where there is no energy between the atoms of the solid object, so there will no radiation emited, which means that there is no energy emited.

This has a lot of sense, if the object has temperature equal to zero, is logical to think that it can not radiate energy in the form of heat (or in any form)

True as known as "Absolute Kelvin" =
-273 degress Celsius not heat energy is left among atoms.

When a compression wave travel through a median, which way does matter in the median move?

Answers

Matter will move upwards or outwards depending on the direction of the compression wave