Answer:
The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.
Explanation:
Given that,
Force F = 1500 pounds
Distance d = 40 feet
Time t = 40 sec
Work done :
The work done is the product of the force and distance.
The work done is defined as,
Where, W = work
F = force
d = distance
Put the value into the formula of work
Power:
The power is equal to the work done divided by time.
The power is defined as,
Where, P = power
W = work
t = time
Put the value into the formula of power
Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.
Displacement:
Distance: The total distance traveled is the sum of the individual distances traveled in each direction. In this case, you moved 25 meters North and then 50 meters West. So, the total distance is:
Distance = 25 m (North) + 50 m (West) = 75 meters
Displacement: Displacement is the straight-line distance from the starting point to the final point, taking into account both the distance and direction. To calculate the displacement, you can use the Pythagorean theorem because the motion is in perpendicular directions (North and West).
Displacement = √((25 m)² + (50 m)²)
Displacement = √(625 m² + 2500 m²)
Displacement = √(3125 m²)
Displacement = 55.9 meters (rounded to one decimal place)
-the total displacement is approximately 55.9 meters in a direction that is between North and West.
Answer: +1.77
Explanation:
Big dipper is the asterism made of seven bright stars in Ursa Major constellation. An asterism a pattern formed by joining the bright stars in the night sky. On the other hand, whole night sky is divided into 88 areas called constellations. These asterisms are used to identify the constellations.
The brightest star of the big dipper is Alioth which is the 32nd brightest star in the night sky. Its apparent magnitude is +1.77.
The rate at which the voltage of the given circuit is changing is gotten to be;
dV/dt = 0.452 V/s
We are given;
Current; I = 3 A
Resistance 1; R1 = 4Ω
Resistance 2; R2 = 3Ω
dR1/dt = 0.4 Ω/s
dR2/dt = 0.2 Ω/s
dI/dt = 0.02 A/s
Now, formula for voltage with resistors in parallel is;
1/V = (1/I)(1/R1 + 1/R2)
Plugging in the relevant values, we can find V;
1/V = (1/3)(1/4 + 1/3)
Simplifying this gives;
1/V = 0.194
Now, we want to find the rate at which the voltage is charging, we need to find dV/dt.
Thus, let us differentiate 1/V = (1/I)(1/R1 + 1/R2) with respect to t to get;
(1/V)²(dV/dt) = [(1/i²)(di/dt)(1/R1 + 1/R2)] + (1/I)[(1/R1²)(dR1/dt) + (1/R2²)(dR2/dt)]
Plugging in the relevant vies gives us;
0.194²(dV/dt) = [(1/3²)(0.02)(¼ + ⅓)] + (⅓)[(1/3²)(0.4) + (1/4²)(0.3)]
>> 0.037636(dV/dt) = 0.001296 + 0.0157
>> dV/dt = 0.016996/0.037636
>> dV/dt = 0.452 V/s
Read more at; brainly.com/question/13539417
Answer:
Explanation:
As we know that two resistors are in parallel
so we have
where we know that
so we have
now to find the rate of change we have
now from above equation we have
a. True
b. False
Answer: true
Explanation: The zero Kelvin is the point where there is no energy between the atoms of the solid object, so there will no radiation emited, which means that there is no energy emited.
This has a lot of sense, if the object has temperature equal to zero, is logical to think that it can not radiate energy in the form of heat (or in any form)