Answer:
x = 5√2
y = 5√6
z = 5√3
ΔABC ~ ΔBDC ~ ΔADB
Step-by-step explanation:
ΔABC, ΔBDC, and ΔADB are all similar triangles to each other.
By definition of similar triangles, the corresponding sides have the same ratios.
CD from ΔBDC corresponds to BD from ΔADB, and BD from ΔBDC corresponds to AD from ΔADB. So:
CD / BD = BD / AD
10 / x = x / 5
x² = 50
x = 5√2
Since ΔBDC is right, we can use the Pythagorean Theorem to solve for y:
CD² + BD² = BC²
10² + (5√2)² = y²
y² = 100 + 50 = 150
y = 5√6
Again, since ΔΔABD is right, we can use the Pythagorean Theorem to solve for z:
AD² + BD² = AB²
5² + (5√2)² = z²
z² = 25 + 50 = 75
z = 5√3
Answer:
x² = 5×10
x = √50
x = √5²×2
x = 5√2
z² = 5² + (5√2)²
z = √25 + 50
z = √75
z = √5²×3
z = 5√3
y² = 10² + (5√2)²
y = √100 + 50
y = √150
y = √5²×6
y = 5√6
x = 5√2
y = 5√6
z = 5√3
ΔABC ≈ ΔBDC ≈ ΔADB
Step-by-step explanation:
Let the initial height of the tree.
It is given that the tree grows inches every month.
So,in months,the tree grows
inches.
The final height of the tree after months is the sum of its initial height and its growth in
months.
So,
Given that
So,
So,
hence,P(urn-1)=8/18,p(urn-2)=10/13
Probability is number of favorable outcomes by total no. of outcomes
No. of favorable outcomes / total no. of outcomes.
Given urn-1- 10 green balls and 8 balls .
and urn -2 - 3 green balls and 1- red balls .
ball is taken out from both the baxes
probability of red ball= p(urn1
P(urn-1)=8/18
p(urn-2)=10/13
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