Below are five number sequences. Which ones are geometric sequences?Check all that apply.A- 1 2 3 4 53 9 27 81 343B. 2, 3, 5, 9, 17,C. 3, -12, 48, -192, 768,D. 3, -15, -33, -51, -69,E., 1 1 1 1

The option (D) 126° + (720n)°, for any integer n is correct for any integer n.

What is coterminal angles?

Two different angles that have the identical starting and ending edges termed coterminal angles however, since one angle measured clockwise and the other determined counterclockwise, the angles' terminal sides have completed distinct entire rotations.

We have an angle of 126 degree

As we know from the definition of the coterminal angle.

If any angle θ the coterminal angles are:

= θ + 360n  (for any integer n)

Plug n = 2n

= θ + 720n  (for any integer n)

Also represents the coterminal angle.

Thus, the option (D) 126° + (720n)°, for any integer n is correct for any integer n.

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Answer:

1 》let equal side be X and other side y

now, length of y= 2x sin teta/2

=12.3×sin42/2

=12.3 × sin21

=4.407

Answer: 10

Step-by-step explanation: Because 10times X when X=6 is 60 then 5 times Y when Y=10 makes it 50 then subtract the two numbers

60-50=10

Final answer:

The value of the expression 10x - 5y when x = 6 and y = 10 is 10.

Explanation:

The expression given is 10x - 5y. We are asked to determine the value of this expression when x = 6 and y = 10. To do this, we replace x and y in the expression with these given values:

10*6 - 5*10 = 60 - 50 = 10

So, when x = 6 and y = 10, the value of the expression 10x - 5y is 10.

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Answer:

To find the x-intercepts of the parabola defined by the equation y = 2x² - 8x + 10, you need to set y equal to zero (because x-intercepts occur when y is zero) and solve for x.

So, you have:

0 = 2x² - 8x + 10

Now, you can use the quadratic formula to solve for x:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 2, b = -8, and c = 10. Plug these values into the formula:

x = (-(-8) ± √((-8)² - 4 * 2 * 10)) / (2 * 2)

x = (8 ± √(64 - 80)) / 4

x = (8 ± √(-16)) / 4

Since the discriminant (the value inside the square root) is negative, there are no real solutions, which means this parabola does not have x-intercepts in the real number system.

So, there are no ordered pairs (x1, y1) and (x2, y2) for x-intercepts because there are no x-intercepts for this parabola in the real number system.

Step-by-step explanation:

Certainly, let's find the x-intercepts step by step for the equation:

y = 2x² - 8x + 10

Step 1: Set y to zero because x-intercepts occur when y equals zero:

0 = 2x² - 8x + 10

Step 2: Now, we want to solve this equation for x. We can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this formula:

a is the coefficient of the x² term (which is 2 in this case).

b is the coefficient of the x term (which is -8).

c is the constant term (which is 10).

Step 3: Plug the values of a, b, and c into the formula:

x = (-(-8) ± √((-8)² - 4 * 2 * 10)) / (2 * 2)

Step 4: Simplify the equation inside the square root:

x = (8 ± √(64 - 80)) / 4

x = (8 ± √(-16)) / 4

Step 5: Now, notice that we have a square root of a negative number (√(-16)). In the real number system, we can't take the square root of a negative number. This means there are no real solutions for x.

Step 6: Since there are no real solutions, there are no x-intercepts for this parabola in the real number system. Therefore, there are no ordered pairs (x1, y1) and (x2, y2) for x-intercepts in this case.