The average high temperature in a town for the month of July is 36.71 C. One day in July the temperature reached a record high of 39.52 c. How much higher is the record high temperature than the average high temperature?
Answers
Answer:
2.81 C
Step-by-step explanation:
39.52-36.71 = 2.81 C
Hi!
The answer is simple. :) Just subtract the record high temperature (39.52) and the average high temperature (36.71)
Your answer would be 2.81.
Hope this helps, have a wonderful day/night! :)
Related Questions
Find the x-intercept of the parabola of with vertex (1,20) and the y-intercept (0,16). write your answer in this form: (x1,y1),(x2,y2)
(sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^
HEEEEEELPquestion in the attached picture
Joe drove 538 miles in 9 hours and 15 minutes. What was his average speed per hour
B.Trail X has a positive slope (it runs uphill).
C.Trail X has a negative slope (it runs downhill).
D.Trail Y is steeper than trail X.
Answers
Answers
Help me solve this problem
Answers
10n-7=23
add 7 to both sides
10n=30
divide both sides by 10
n= 3
Answer:
3
To find:
n
Step-by-step explanation:
бn - 7+ 4n = 23
10n-7 = 23
10n = 23 + 7
10n = 30
n = 30/10
n = 3
hope it helps you!!
Answers
Answer:
b=9
Step-by-step explanation:
Answers
Answers
To find the length of each flight, we can use the formula: distance = speed x time.
Let's assume the length of the outbound flight (from the starting point to the destination) is x miles. Since the flight averages 460 miles per hour, the time taken for the outbound flight can be calculated as x/460 hours.
For the return flight, which averages 500 miles per hour due to the tailwind, the time taken can be calculated as x/500 hours.
The total flying time for both flights is given as 4 hours and 48 minutes, which can be converted to hours as 4 + 48/60 = 4.8 hours.
Using this information, we can set up the equation:
x/460 + x/500 = 4.8
To solve this equation, we can multiply through by the common denominator of 460 and 500, which is 230,000:
500x + 460x = 4.8 * 230,000
960x = 1,104,000
x = 1,104,000 / 960
x ≈ 1,150
Therefore, the outbound flight is approximately 1,150 miles long.
To find the duration of each flight, we can substitute this value back into the equations:
Outbound flight duration = 1,150 miles / 460 miles per hour ≈ 2.5 hours
Return flight duration = 1,150 miles / 500 miles per hour = 2.3 hours
Hence, the outbound flight lasts approximately 2 hours and 30 minutes, while the return flight lasts approximately 2 hours and 18 minutes.