Answer:
The length of the ∠CXA is 70° 55'
Step-by-step explanation:
Given = ∠BXA = 30° 20', ∠CXB = 40° 35'
To find = ∠CXA =?
Solution:
∠BXA + ∠CXB = ∠CXA (from the diagram)
30° 20' + 40° 35' = ∠CXA
∠CXA = 70° 55'
In right triangle XYZ, _X and Z are complementary angles and cos(x)is 11. What is sin(Z)?
9
OA.
B. 1/2
11
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C.
20
9
20
11
D.
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Answer:
A
Step-by-step explanation:
Using the cofunction identity
cos(90 - x) = sinx , or
sin(angle) = cos(complement of angle)
x and z are complementary angles , x + z = 90 , then
sinz = cosx =
In right triangle XYZ, if X and Z are complementary and cos(X) is 11, sin(Z) should be 11 as well. Nevertheless, the cosine of an angle in a standard triangle can't exceed 1 in absolute value, suggesting an error in the provided data.
In a right triangle, if two angles are complementary, their sum equals 90 degrees. In the case of right triangle XYZ, angles X and Z are complementary. This means that angle Z is the complement of angle X. In trigonometry, the sine of an angle is equal to the cosine of its complement.
Therefore, sin(Z) = cos(X).
Given that cos(X) is 11, it follows that sin(Z) is also 11. However, it is essential to point out that the cosine of an angle can't exceed 1 in absolute value in a standard triangle, so there might be a misprint or misunderstanding in the problem. If cos(X) falls within a valid range, then sin(Z) should equal cos(X).
#SPJ2
Is this asking to find the coordinates, or to find the distance?
Answer:
(nearest tenth)
Step-by-step explanation:
Given:
G(-2, -3)
H(0, 3)
Required:
Distance between point G and H = GH
Solution:
Distance between G(-2, -3) and H(0, 3):
Let,
(nearest tenth)
b) write and equation to model this situation
Show work plz