Thomas is using a drawing program to complete a construction. Which construction could he be completing? Select one of the following:

a. An equilateral triangle inscribed in a polygon
b. A square inscribed in a circle
c. A regular pentagon inscribed in a polygon
d. A regular hexagon inscribed in a polygon

Answers

Answer 1

Answer: The right answer for the question that is being asked and shown above is that: "b. A square inscribed in a circle." Thomas is using a drawing program to complete a construction. The construction that could he be completing is a square inscribed in a circle

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The variables x and y are directly proportional, and y=2 when x=3. What is the value of y when x=9

Answers

$If\ x\ and\ y\ are\ directly\ proportional\ then\ (y)/(x)\ is\ constans\n---------------------------\n\n(2)/(3)=(y)/(9)\n\ncross\ multiply\n\n3y=2*9\n\n3y=18\ \ \ \ |divide\ both\ sides\ by\ 3\n\ny=6$

you cross multiply and you should get i think 6?

the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle

Answers

$l-the\ length\nl+8-the\ width\nA=172\ cm^2\n\nA=lengtf\cdot width\n\nsubtitute\n\nl(l+8)=172\n\nl^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\n\nl^2+8l-172=0\na=1;\ b=8;\ c=-172\n\n\Delta=b^2-4ac\n\n\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\n\nl_1=(-b-\sqrt\Delta)/(2a)\ and\ l_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=√(752)=√(16\cdot47)=4√(47)\n\nl_1=(-8-4√(47))/(2\cdot1)=-4-2√(47) < 0\n\nl_2=(-8+4√(47))/(2\cdot1)=-4+2√(47) > 0\n\nThe\ width:l+8=-4+2√(47)+8=4+2√(47)\n\nAnswer:\boxed{length=(2√(47)-4)cm;\ width=(4+2√(47))cm}$
$length\approx9.71cm;\ width\approx17.71cm$

the functions b(n)= 6n and represents the number of light bulbs B(n) that are needed for n chandeliers how many light bulbs are needed for 15 chandeliers

Answers

b(n) = 6n

b(15) = 6(15)
b(15) = 90....so 90 light bulbs are needed for 15 chandeliers

Determine the solution to the system of equations by using substitution. Y=4x+10
Y=-5x-10

Answers

Steps:
1. Substitute the y in 4x + 10 with -5x-10
-5x-10= 4x + 10
2. Add 5x on both sides
-10= 9x + 10
3. Subtract 10 on both sides
-20= 9x
4. Divide by 9 on both sides
5. Your answer is
X= -20/9

$y=4x+10\ny=-5x-10\n\n4x+10=-5x-10\n9x=-20\nx=-(20)/(9)\n\ny=4\cdot(-(20)/(9))+10\ny=-(80)/(9)+(90)/(9)\ny=(10)/(9)\n$

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