What equation could be used to find how many grams of mass is in 15.6 kilograms
Answers
so , mass by grams = 15.6 *1000 = 15600 grams
Related Questions
Find the measure of each angle indicated
Monica’s school band held a car wash to raise money for a trip to a parade in New York City. After washing 125 cars, they made $775 from a combination of $5.00 quick washes and $8.00 premium washes.Let x represent the number of quick washes and let y represent the number of premium washes. Which system of linear equations represents the situation? 5x + 8y = 775 and x + y =125 5x – 8y = 125 and x + y = 775 5x + 8y = 775 and x – y = 125 5x – 8y = 125 and x – y = 775
Solve the equation by completing the square x^2 - 7x - 4 = 0 A. 7.53, -0.53 B. -7.53, -0.53 C. -7.53, 0.53 D. 7.53, 0.53
Complete the expansion of this expression by finding the values of the capitalised pronumerals4x (5 + 4y + 3x) + 3y (1 + x) = Ax² + Bx + Cxy + DyA=B=C=D=
How many seconds did it take for the object to hit the ground?
How many seconds did it take for the object to reach 1000 feet
Answers
Answer:
time = 0 seconds
Time to hit ground = 7.906 seconds
time = 0 seconds
Step-by-step explanation:
t = 0
-16(0)^2 +1000 = 1000
Time for ball to reach ground:
-16t^2 +1000 = 0
-16t^2 = -1000
t^2 = -1000/-16
t = squareRoot (-1000/-16) = 7.906 seconds
Answers
Answer
2
Explanation
The two lines in the diagram are secants meeting outside the circle.
The products of a secant and the extension of the chord of one line is equal to the products of a secant and the extension of the chord of the other line.
∴ 3(3+5) = 4(4+x)
3 × 8 = (4×4)+(4×x)
24 = 16 + 4x
4x = 24 - 16
4x = 8
x = 8/4
= 2
Answers
The solution set of the inequality 9x ≥ 117 is [9, ∞).
What are inequalities and their types?
Inequality is a relation that compares two numbers or other mathematical expressions in an unequal way.
The symbol a < b indicates that a is smaller than b.
When a > b is used, it indicates that a is bigger than b.
a is less than or equal to b when a notation like a ≤ b.
a is bigger or equal value of an is indicated by the notation a ≥ b.
Given, An inequality 9x ≥117.
Dividing both sides by 9 we have,
(9/9)x ≥ 117/9.
x ≥ 13.
Therefore, The solution set of the inequality is [9, ∞).
learn more about inequalities here :
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Step-by-step explanation:
which number or numbers below belong to the solution set of the inequality check all that apply 9x>117
Answers
5x-9 = 3x+3
2x-9 = 3
2x = 12
x= 6
plz mark branliest, hopoe this helps :)
Answers
Answers
The perimeter of the second triangle is 90 units.
What are similar figures?
Similar figure are zoomed in or zoomed out (or just no zoom) version of each other. They are scaled version of each other, and by scale, we mean that each of their dimension(like height, width etc linear quantities) are constant multiple of their similar figure.
So, if a side of a figure is of length L units, and that of its similar figure is of M units, then:
where 'k' will be called as scale factor.
The linear things grow linearly like length, height etc.
For this case, the two considered triangles are similar. Thus:
A side of first triangle = k times corresponding side of its similartriangle
where k is the scale factor, constant for one pair of similar triangles.
We're given that:
Sides of first triangle are of 8,10 and 12 unit length.
Smallest side of second triangle is of 24 units.
Now, smallest side of first triangle will correspond to the smallest side of its similar triangle.
For first triangle, the smallest side is of 8 units (8 is smaller than 10 and 12, the other two sides).
Let the sides of second triangle be of S = 24 units, M units, and L units.
where M is middle sized side and L is largest side of second triangle.
Let the scale factor be 'k'.
Then, we get:
Smallest side of first triangle = k × smallest side of its similar triangle
Similarly, middle sized side of first triangle = (1/3) × middle sized side of second triangle
units.
Thus, the length of middle sized side of second triangle is 30 units.
Largest side of first triangle = (1/3) × Largest side of second triangle
units.
Thus, the length of middle sized side of second triangle is 30 units.
Perimeter of the second triangle = sum of length of its sides
= S + L + M = 24 + 30 + 36 = 90 units.
Thus, the perimeter of the second triangle is 90 units.
Learn more about scale factor here:
the other 2 are 30 and 36