Answer:15 seniors served on the student council during their freshman year, 14 seniors served during their sophomore year, 16 seniors served during their junior year, and 3 seniors have never served before.
Step-by-step explanation:
Using inclusion and exclusion principles, we find that 2 seniors served on the student council during each of the four years in high school.
The problem can be solved using the Principle of Inclusion and Exclusion (PIE), a common technique in combinatorial mathematics. First, we add the number of seniors serving in their freshman, sophomore, and junior years: 3 (never served) + 10 (junior) + 9 (sophomore) + 11 (freshman) giving us 33.
Then, we subtract the number of seniors who served during both sophomore and junior years, freshman and junior years, and freshman and sophomore years: 33 - 5 (sophomore and junior) - 6 (freshman and junior) - 4 (freshman and sophomore). This results in 18.
However, from the initial condition we know that there are 20 seniors in total. Therefore, the two 'extra' seniors must have served all four years in high school. Thus we find that 2 seniors served on the student council during each of the four years in high school.
#SPJ2
Answer:
1,2, and 5
Step-by-step explanation:
i had a question similar and those were the correct ones for me I don't know about the other ones but I'm assuming they aren't correct
3(x + 4) ≥ 5x – 123
4,000 + 800 + 20+3=
Answer:
4823 is the answer you're welcome