How many cycles will occur between t=2 and t=3.5 seconds?
The number of cycles that will occur between t = 2 and t = 3.5 seconds is 384.
Given, y = 8 sin(512πt)
where t = time in seconds.
The standard equation of a sine wave is:
y = A sin(2πfx + B) + C
where A exists the amplitude
f exists the frequency
B exists the phase shift
C is the vertical offset.
In this case:
2πf = 512π
f = 256
This means there are 256 cycles per second.
The number of cycles between t = 2 and t = 3.5 exists:
(3.5 − 2) × 256
= 384
Therefore, the number of cycles that will occur between t = 2 and t = 3.5 seconds is 384.
To learn more about the standard equation of a sine wave
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Answer:
384
Step-by-step explanation:
Standard equation of a sine wave is:
y = A sin(2πf x + B) + C
where A is the amplitude, f is the frequency, B is the phase shift, and C is the vertical offset.
In this case:
2πf = 512π
f = 256
This means there are 256 cycles per second. The number of cycles between t = 2 and t = 3.5 is:
(3.5 − 2) × 256
384
Answer:
A=lw
A=3×3
A=9
Explanation
b. (0, -3)
c. (3, 0)
d. (5, 0)
e. (0, -5)
for all integers x, 1/x less than or equal to x
6x-2y=5
3x+2y=-2