PHYSICS HIGH SCHOOL

What type of reaction occurs in the cores of stars to create their tremendous amounts of energy?a. fusion
b. fission
c. physical
d. chemical

Answers

Answer 1
Answer: The correct answer is A.

Related Questions

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What is the half life of each of these radioactive isotopes?a radioactive isotope decreased to one-fourth its original amount in 18 months.
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A car travels from boston

Which statement explains why a blue house looks blue?The house reflects mostly red and green light
The house absorbs mostly blue light
The house reflects mostly blue light
The house reflects every color expect blue

Answers

Answer: The house reflects mostly blue light.

Explanation: The color of an object as seen by our eyes is determined by the color of the light that they reflect.

In case of a blue painted house, all the other colors of white light ( which is a combination of multiple colors) falling on the house are absorbed and only the blue colored light gets reflected back. Hence the house appears to be blue to our eyes.
The house reflects mostly blue light

Which type of wave can be transmitted through the vacuum of space ?

Answers

Answer: The correct answer is electromagnetic wave.

Explanation:

Electromagnetic wave is wave in which the electric field and the magnetic field are perpendicular to each other. Both fields are directed to the direction of the propagation of the wave.

Electromagnetic wave is transverse in nature. It travels with the speed of the light. It does not need medium to travel. It can be transmitted through the vacuum of space.

Therefore, the correct answer is electromagnetic wave.

An oscillating bock-spring system has a mechanical energy of 1.0 J, an amplitude of 0.10 m, and a maximum speed of 1.2 m/s. Find (a) the force constant of the spring, (b) the mass, and (c) the frequency of oscillation.

Answers

Answer:

a) F = 20 N

b) m = 1.39 kg

c) f = 1.909 Hz

Explanation:

Given

E = 1 J

A = 0.1 m

vmax = 1.2 m/s

a) F = ?

b) m = ?

c) f = ?

Solution

a) We apply the equation

E = 0.5*k*A²

then

k = 2*E/A²

k = 2*1 J/(0.1 m)²

k = 200 N/m

then we use the equation

F = kA

F = (200 N/m)(0.1 m)

F = 20 N

b) We use the formula

E = K + U

if U = 0 J

then

E = K = 0.5*m*v²

⇒  m = 2*K/v²

m = 2*1 J/(1.2 m/s)²

m = 1.39 kg

c) we apply the equation

f = (1/2π)√(k/m)

then

f = (1/2π)√(200 N/m/1.39 kg)

f = 1.909 Hz

Answer:

a)k = 200.016\,(N)/(m), b)m = 1.389\,kg, c)f = 0.524\,hz

Explanation:

a) The maximum speed of the oscillating block-spring system is:

v_(max) = \omega \cdot A

The angular frequency is:

\omega = (v_(max))/(A)

\omega = (1.2\,(m)/(s) )/(0.1\,m)

\omega = 12\,(rad)/(s)

The mass of the system is:

E = (1)/(2)\cdot m\cdot v_(max)^(2)

m = (2\cdot E)/(v_(max)^(2))

m = (2\cdot (1\,J))/((1.2\,(m)/(s) )^(2))

m = 1.389\,kg

The spring constant is:

\omega = \sqrt{(k)/(m) }

k = \omega^(2)\cdot m

k = (12\,(rad)/(s) )^(2)\cdot (1.389\,kg)

k = 200.016\,(N)/(m)

b) The mass is:

m = 1.389\,kg

c) The frequency of oscillation is:

\omega = 2\pi\cdot f

f = (2\pi)/(\omega)

f = (2\pi)/(12\,(rad)/(s) )

f = 0.524\,hz

Car design features that is intended to increase friction when cornering or stopping?

Answers

Answer: tyre made out of rubber, tread pattern on wheels

Explanation:

the material of rubber generally grips better than other materials whilst still allows the car to move smoothly

tread patterns are essential on all tires as it increases the traction between the wheels and the road which increases the friction

Assume that all four H-R diagrams below represent a star in different stages of its life, after it starts to fuse hydrogen in its core. Rank the HR diagrams based on when each stage occurs, from first to last.

Answers

Answer and explanation;

-The diagram at the left represents the Sun (or any other one-solar-mass star) as a hydrogen-burning main-sequence star, with spectral type G and one solar luminosity. The next diagram shows the Sun after it has exhausted its core hydrogen and left the main sequence, making it a sub-giant with energy generated by hydrogen burning in a shell around an inert helium core.

-The third diagram shows the Sun a little later; its energy source is still hydrogen shell burning, but at this point it has expanded in size so much that it is a red giant. The final diagram (far right) shows the white dwarf corpse of a one-solar-mass star; it is hot because it is the exposed core of the dead star, but dim because it is small in size.
The right answer for the question that is being asked and shown above is that: "1-4-3-2." (main sequence-->red giant-->supergiant-->white dwarf). Assume that all four H-R diagrams below represent a star in different stages of its life, after it starts to fuse hydrogen in its core.

Which wave top or bottom has the larger frequency

Answers

The question is simple and for the answer to the question above, it must be the bottom one because it has longer wavelengths and Because the bottom ones has 3 crests (wavelengths)
I hope my answer helped you somehow. Have a nice day!
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