Answer: Option B.
Step-by-step explanation:
By definition, the graph of a proportional relationships is a straight line that passes through the origin (Remember the the origin is at ).
Then, the equation have the following form:
Where "k" is the constant of proportionality (or its slope)
Then, since the Sara graphs a line that represent a proportional relationship, you can conclude that the line must pass through the point .
Then:
The set of points in Option A could not be on that line, because when
The set of points (Given in Option B) could be on the line that Sara graphs, because it has the point
For the set of points shown in Option C and Option D, you can check if the slope is constant:
Since the slope is not constant, this set of ponts could not be on the line.
Since the slope is not constant, this set of ponts could not be on the line.
Set of points that could be on the line that Sara graphs are:
Option B). (6,8) , (0,0) , (18,24)
Solving linear equation mean calculating the unknown variable from the equation.
Let the linear equation : y = mx + c
If we draw the above equation on Cartesian Coordinates , it will be a straight line with :
m → gradient of the line
( 0 , c ) → y - intercept
Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :
If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :
Let us tackle the problem.
This problem is about Directly Proportional.
If (x₁ , y₁ ) and (x₂ , y₂) are on the line that represent a proportional relationship, then :
Let:
(2,4) ⇒ (x₁ , y₁)
(3,9) ⇒ (x₂ , y₂)
→ not proportional
Let:
(6,8) ⇒ (x₁ , y₁)
(18,24) ⇒ (x₂ , y₂)
→ proportional
Let:
(3,6) ⇒ (x₁ , y₁)
(9,4) ⇒ (x₂ , y₂)
→ not proportional
Let:
(1,1) ⇒ (x₁ , y₁)
(2,1) ⇒ (x₂ , y₂)
→ not proportional
Grade: High School
Subject: Mathematics
Chapter: Linear Equations
Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point
#LearnWithBrainly
Create a real world equality problem, then solve:
Example Problem:
Ana sells at least 220 shirts:
Ana Sold 85 shirts in the first 3 weeks of the month:
How many shirts must Ana sell in the last week of the month?
Solution:
Let S = the number of shirts Ana sells in the last week of the month.
Total Number of Shirts for the month must be greater than 220:
We Write: 85 + S ≥ 220
We Solve the inequality by Subtracting 85 from both sides: S ≥ 135
Therefore, Ana must sell 135 or more shirts in the last week to go on the school trip.
Solve: 85 + s ≥ 220 ========> S ≥ 135
Let's solve your inequality step-by-step.
85 + s ≥ 220
Step 1: Simplify both sides of the inequality.
s + 85 ≥ 220
Step 2: Subtract 85 from both sides.
s + 85 − 85 ≥ 220 − 85
s ≥ 135
Answer:
s ≥ 135
Check Problem:
85 + s ≥ 220 ========> S ≥ 135
We see that =====> 85 + 135 = 220
If Ana sells 135, or more shirts, The total number of shirts she sells that month will be 220 or more ========> Answer Checked
Hope that helps!!!!!!!!!!! : )
Answer:19
Step-by-step explanation:you get 19
Answer:19
Step-by-step explanation:
First, what you would do is multiply 140 and 20%. Which would give you: 28
Then you would multiply 28 by 4 and get 112
Hope this helps!!(: