The nthterm for the sequence is 4n + n².
The two consecutiveterms in the sequence where the difference will be 245 are 120 and 121.
A sequence is a group of numbers where there is a relation between each consecutive value.
We have,
5, 12, 21, 32,
We see that,
The difference between the consecutive numbers is 7, 9, 11, 13, 15,
We can make a formula for the nth term.
4n + n²
Where n = 1, 2, 3, 4, ,,,,
Now,
Let the two consecutiveterms be n and (n +1).
4(n + 1) + (n + 1)² - 4n - n² = 245
4n + 4 + n² + 2n + 1 - 4n - n² = 245
4 + 2n + 1 = 245
2n + 5 = 245
2n = 240
n = 120
And,
n + 1 = 121
So,
The two consecutiveterms in the sequence where the difference will be 245 are 120 and 121.
Thus,
The nthterm for the sequence is 4n + n².
The two consecutiveterms in the sequence where the difference will be 245 are 120 and 121.
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b.196 m3
c. 70 m3
d.392 m3
f(x) = (9x - 1)(7x - 3)
Answer:
63x^2-34x+3
Step-by-step explanation:
For random samples of 100 seniors, 68% of the sample means fall between ____ and ___
Answer:
For random samples of 100 seniors, 68% of the sample means fall between 340 and 520
Step-by-step explanation:
As a property of normal distribution, 68% of sample means fall between mean - sigma(430 - 90 = 340) and mean + sigma (430 + 90 = 520) (here, sigma is standard deviation).
Hope this helps!
:)