Answer:
two-way relative frequency tables
Step-by-step explanation:
please tell me if i am wrong.
Answer:
t-chart
Step-by-step explanation:
The area of the trapezoid is 35 cm².
Solution:
The figure is splitted into two shapes.
The reference image is attached below.
One shape is rectangle and the other is triangle.
Length of the rectangle = 6 cm
Width of the rectangle = 5 cm
Area of the rectangle = length × width
= 6 × 5
= 30 cm²
Base of the triangle = 8 cm - 6 cm = 2 cm
Height of the triangle = 5 cm
Area of the triangle =
= 5 cm²
Area of the trapezoid = Area of the rectangle + Area of the triangle
= 30 cm² + 5 cm²
= 35 cm²
The area of the trapezoid is 35 cm².
Given equation is y=2x+7 and
Let's simplify the 2nd equation before we can start graph so that calculation will be easy
multiply both sides by 2 to cancel out fractions
y=2x+7
which is exactly same as the first equatoin so graph of both will be exactly same and solution will be infinitely many solutions.
y=2x+7 has y-intercept 7 so first point will be (0,7). Slope is 2 so rise 2 unit up then 1 right and graph the new point.
to head back home. What is the total distance that layla walked? (HINT: Final answer is
perimeter of the triangle park)
120 yd.
PARK
PARK
50 vd
Oak St
1
Park Rd
Total distance walked by Layla is 300 yards
Solution:
Given that,
Layla is walking in a rectangular park
She walks one side that is 50 yards and then the other side that is 120 yards
Length = 120 yards
Width = 50 yards
Layla develops a cramp in her leg and walks diagonally through the park to head back home
Let us find the length of diagonal of rectangle
Thus length of diagonal is 130 yards
What is the total distance that layla walked?
Given that Final answer is perimeter of the triangle park
The diagonal and length and width forms a right angle triangle
Perimeter of triangle = diagonal length + width + length
Perimeter of triangle = 130 + 50 + 120 = 300
Thus total distance walked by Layla is 300 yards