trisha standford earns $300 a week plus a 15% commission only on sales she makes after her first $1,000 in sales if ms standfords sales for one week are $2,500 what is her gross pay for that week
Answers
Answer:
Her gross pay for that week=$525
Step-by-step explanation:
Step 1: Express the gross pay
The gross pay can be expressed as follows;
A=F+(R×T)
where;
A=the gross pay per week
F=fixed income per week
R=commission rate
T=total commission sales
In our case;
F=$300 a week
R=15%=15/100=0.15
T=(2,500-1,000)=$1,500
replacing;
A=300+(15% of 1,500)
A=300+(0.15×1,500)
A=300+225=525
A=$525
Her gross pay for that week=$525
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6. The lengths of two sides of a triangle are 5 cm and 8 cm. Between what two measuresshould the length of the third side fall
Answers
let h = horse, let c = cow, let p = pig
so,
hcp
hpc
cph
chp
phc
pch
so, that is 6 different ways she can arrange it.
pig, cow, horse
pig, horse, cow
horse, pig, cow
horse, cow, pig
cow, pig, horse
cow, horse, pig
Answers
Using common denominator of 6:
They should use
Answers
Final answer:
The circular exercise run provides more area for Rico's dog to run than the rectangular lawn. This is determined by calculating the maximum possible area for a rectangle with a perimeter of 36 meters and a circle with a circumference of 36 meters.
Explanation:
To answer which shape will give Rico's dog more area to run, we need to calculate the areas of the given shapes - a rectangle and a circle - using their respective perimeters/circumferences.
For a rectangle with a perimeter of 36 meters, one plausible dimension could be a rectangle with a length of 10 meters and a width of 8 meters, giving an area of 80 square meters assuming the shape is a square. (This gives the maximum area for a given perimeter).
The circumference of a circle is given by the formula 2πr, where r is the radius of the circle. If the circumference is 36 meters, then the radius would be 36/(2π) ≈ 5.73 meters. The area of this circle would then be πr², approximately 103.07 square meters.
In conclusion, the circle will offer more area for Rico's dog to run, despite the rectangular lawn and circular exercise run having the same perimeter and circumference lengths respectively.
Learn more about Area Comparison here:
#SPJ3
B.–4 must be factored from –4x2 + 2x
C.x must be factored from –4x2 + 2x
D.–4 must be factored from –4x2 – 7
Answers
first, the coeieicne infront of x^2 term musbe 1
so if you have
y=ax^2+bx+c
isolate x terms and undistribute a
y=a(x^2+(b/a)x)+c
B is answer
Answer:
B
Step-by-step explanation:
Right on Edge
B) P(z≤-a)-P(-a≤z≤a)+P(z≥a)
C) P(z≤-a)+P(-a≤z≤a)-P(z≥a)
D) P(z≤-a)+P(-a≤z≤a)+P(Z≥a)
Answers
Therefore, option D is the correct answer.
Answer:
D.
Step-by-step explanation:
Properties of normal distribution-
- The normal curve is symmetrical about the mean (μ).
- The mean is at the middle of the graph and it divides the area into two equal halves.
- The total area under the curve is equal to 1.
The total area under the curve can be divided into parts like,
- area below
, i.e
,
- area between
, i.e
- area above
Therefore,
Answers
We are required to calculate the number of days it would take the apprentice working alone
The number of days it takes the apprentice working alone is 6 days
let
Number of days taken for the carpenter to work alone = x
Number of days taken by the apprentice to work alone = 2x
Number of days taken to work together = 2 days
Work done per day Carpenter = 1/x
work done per day apprentice = 1/2x
work done per day together = 1/2
So,
work done per day together = Work done per day Carpenter + work done per day apprentice
1/2 = 1/x + 1/2x
1/2 = (2 + 1) / 2x
1/2 = 3/2x
cross product
1(2x) = 2(3)
2x = 6
x = 6/2
x = 3 days
Therefore,
Number of days taken by the apprentice to work alone = 2x
= 2(3)
= 6 days
Read more:
Answer:
6 days
Step-by-step explanation:
Let the time taken by Carpenter working alone = days
Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2 days
Time taken working together = 2 days
Work done in one day working together =
Work done in one day by Carpenter working alone =
Work done in one day by apprentice working alone =
Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone = +
= Work done in one day working together =
Time taken by Carpenter alone to complete the work = 3 days
Time taken by Apprentice alone to complete the work = 3 2= 6 days