MATHEMATICS COLLEGE

A disease has hit a city. The percentage of the population infected t days after the disease arrives is approximated by p(t)equals7 t e Superscript negative t divided by 13 for 0less than or equalstless than or equals39. After how many days is the percentage of infected people a maximum? What is the maximum percent of the population infected?

Answers

Answer 1

Answer:

Answer:

t = 13 days

p(13) = 33.47%

Step-by-step explanation:

p(t) is the percentage of the population infected:

p(t) = 7*t*e∧(-t / 13)

where 0 ≤ t ≤ 39 days

we can apply p'(t) = 0 to get number of days where the percentage of infected people is maximum:

p'(t) = (7*t*e∧(-t / 13))' = 7*(t*e∧(-t / 13))' = 7*((t)'*e∧(-t / 13)+t*(e∧(-t / 13)') = 0

⇒ 7*(1*e∧(-t / 13)+t*e∧(-t / 13)*(-1 / 13)) = 7*e∧(-t / 13)*(1 - (t / 13)) = 0

∴ 1 - (t / 13) = 0 ⇒ t = 13 days

then we get the maximum percent of the population infected as follows

p(13) = 7*13*e∧(-13 / 13)

⇒ p(13) = 33.47%

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Answers

Answer:

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Step-by-step explanation:

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The standard deviation of the box is 0.3 approximately.

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Answers

x - the shortest side

x + 28

The sum of these must be equal to the perimeter of the flower bed, so

x + 2x + x + 28 = 184

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Answers

Answer:

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Step-by-step explanation:

The given series is in arithmetic progression since the common difference is same which is 8.

To find the sum of series we can simply apply the formula'

S= n/2( first term + last term)

S is the sum and n is the number of terms

we also need to find the number of terms n

n = (last term- first term)/2 + 1

$n= (403-3)/(8) + 1$

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$s= (51)/(2)(3+403)$

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