MATHEMATICS HIGH SCHOOL

If school starts at 8:30 a.m. and ends at 3:20 p.m., how long is the school day?5 hours and 10 minutes
11 hours and 50 minutes
6 hours and 50 minutes
6 hours and 10 minutes

Answers

Answer 1

Answer:

The school day is 6 hours and 50 mins long.

Given to us,

school starts at 8:30 a.m.

ends at 3:20 p.m.,

To understand it easier, Let's round of the time to the nearest values,

8:30 a.m. ≈ 9:00 A.m.

3:20 p.m. ≈ 3:00 p.m.

Now, as we can see at 8:30 a.m. to 9:00 A.m., there is an extra time of 30 mins while at 3:20 p.m. to 3:00 p.m., there is an extra time of 20 mins, therefore we will have an extra time of 50 mins overall if we calculate the time from 9:00 A.M. to 3:00 p.m.

Calculation

dividing the time from 9:00 a.m. to 3:00 p.m. into two parts,

9:00 a.m. to 3:00 p.m = 9:00 a.m. to 12:00 p.m + 12:00 p.m. to 3:00 p.m

From 9:00 a.m. to 12:00 p.m the difference is of 3 hours, and the difference from 12:00 p.m. to 3:00 p.m is also 3 hours.

Therefore, the time between 9:00 a.m. to 3:00 p.m is of six hours but we also have extra 50 mins left.

Hence, the school day is 6 hours and 50 mins long.

Learn more about Time:

brainly.com/question/2570752

Answer 2

Answer: School day is 6 hours and 50 minutes long.

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What is perpendicular to y= 3x -9 and passes through the point (3,1)

Answers

$(3,1) , \ \ y= 3x -9 \n \n The \ slope \ is :m _(1) =3 \n \n If \ m_(1) \ and \ m _(2) \ are \ the \ gradients \ of \ two \ perpendicular \n \n lines \ we \ have \ m _(1) \cdot m _(2) = -1 \n \n3\cdot m_(2)=-1 \ \ /:3\n \n m_(2)=-(1)/(3)$

$\Now \ your \ equation \ of \ line \ passing \ through \ (3,1) would \ be: \n \n y=m_(2)x+b \n \n1=-(1)/( 3) \cdot3 + b$

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Convert the following decimal to a common fraction. Reduce to lowest terms 0.2 = 2/1 0/2 1/2 1/5

Answers

0.2 = $(2)/(10) = (1)/(5)$
So, $(1)/(5)$

A fish swims at a rate of 8 feet per second. How far can the fish swim in 23
seconds?

Answers

Answer:

8(23) so 184

Step-by-step explanation:

Answer:

it would have traveled 184 feet

Step-by-step explanation:

Since the rate in which the fish is swimming is 8 feet per second and given that we have to figure out the distance in which it traveled in 23 seconds, we can just multiply 8× 23 to receive 184 feet in 23 seconds.

Which system of equations has the same solution as the system below? 2x+2y=16 and 3x-y=4

Answers

4x divide 16 3x-4y it is the answer

Is 1/sec^2(θ) the same as cos^2(θ)

Answers

$(1)/(sec^2\theta)=cos^2\theta\n\nL=(1)/(\left((1)/(cos\theta)\right)^2)=(1)/((1)/(cos^2\theta))=1:(1)/(cos^2\theta)=1\cdot(cos^2\theta)/(1)=cos^2\theta=R$