Which pair of measurements is not equivalent?4 lb., 64 oz.
3 tons, 6,000 lb.
108 oz., 8 lb.
10,000 lb., 5 tons

Answers

Answer 1
Answer: If you would like to know which pair of measurements is not equivalent, you can calculate this using the following steps:

1 lb = 16 oz
1 ton = 2,000 lb

4 lb = 4 * 16 oz = 64 oz
3 tons = 3 * 2,000 lb = 6,000 lb
8 lb = 8 * 16 oz = 128 oz
5 tons = 5 * 2,000 lb = 10,000 lb

Not equivalent: 108 oz., 8 lb.

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25.83 is 52.5% of what number

Answers

The question asks to find the unknown number - x and we know that 25.83 represents 52.5% of that number. 52.5 % = 0.525. We can make an equation: 0.525 * x = 25.83, where x is the required number. x = 25.83 : 0.525, x = 49.2. Also we can say that x is 100% and 25.83 is 52.5%. Therefore: x : 25.83 = 100 : 52.5; 52.5 x = 100 * 25.83; 52.5 x = 2583; x = 2583 : 52.5; x = 49.2. Answer: the required number is 49.2.

What is the least common multiple of 5 and 2?

Answers

1 is the least common multiple

A picture frame for a square picture has an area of 80 square inches. What is the length of the picture?

Answers

√(80)
That is approximately 8.94

Sin^2(x)-cos^2(x)=0
Find all the solutions in the interval [0,2pi)
Plz help.

Answers

Hello,
as sin² x -cos² x=cos 2x
The equation is
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==>2x=π/2+kπ
==>x=π/4+kπ/2 with k integer


What is
−5.4−(−3.2)−5.4−(−3.2) ?

Answers

5 BGJHYGFGHFGHFFDRTY

On discovering that her family had a 70% risk of heart attack, Erin took a treadmill test to check her own potential of having a heart attack. The doctors told her that the reliability of the stress test is 67%. The test predicted that Erin will not have a heart attack. What is the probability after the test was taken that she will have a heart attack?0.4051
0.5010
0.4653
0.6632

Answers

Answer:

C.  0.4653

Step-by-step explanation:

This a conditional probability problem where Bayes theorem should be applied.

Applying Bayes theorem,

P(\text{No heart attack}\ |\ \text{Correctly tested})=

\frac{P(\text{Correctly tested}\ |\ \text{No heart attack})\cdot P(\text{No heart attack})}{P(\text{Correctly tested})}

P(\text{Correctly\ tested}\ |\ \text{No\ heart\ attack})=67\%=0.67

P(\text{No\ heart\ attack})=1-P(\text{heart\ attack})=1-0.7=0.3

P(\text{Correctly\ tested})=[P(\text{No\ heart\ attack})* P(\text{Correctly\ tested})]+[P(\text{Heart\ attack})* (\text{Incorrectly\ tested})]

=[0.3* 0.67]+[0.7* 0.33]=0.432

Putting the values,

P(\text{No\ heart\ attack}\ |\ \text{Correctly\ tested})=(0.67* 0.3)/(0.432) =0.4653

There is a probability of 0.4653 or 46.53% chance that she will not have a heart attack even though the test predicts that she will.

Answer:

C= .4653

Step-by-step explanation:

i just took the test and got it right