we have
Step
Let
y=f(x)
Exchange the variable x for y and variable y for x
Clear variable y
Multiply by both sides
Let
therefore
the answer is
the inverse of the function is
the missing value is
Answer:
The Given function is
y= x + 10
To find the inverse of function , we use the following procedure
x=y-10
Now, replace x by y and y by x, we get the inverse of function
y=x -10 , is the inverse of the function, y=x+10.
As, it is given that inverse of f(x) is h(x)
Also, h(x)= 2 x - k-------(1)
Inverse of f(x)=x+10 is ,y= x-10, that is 2 y=2 x- 20------(2)
Comparing 1 and 2, gives
h(x)=2 y
-k=-20
k=20
The difference between the polynomials 5x² + 2x + 11 and 7 + 4x - 2x² is 7x² - 2x + 4 option (D)7x² - 2x + 4 is correct.
Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.
The complete question is:
FIND THE DIFFERENCE:
(5x² + 2x + 11) - (7 + 4x - 2x²)
We have two polynomials:
5x² + 2x + 11 and 7 + 4x - 2x²
We have subtract the polynomial 7 + 4x - 2x² from the polynomial 5x² + 2x + 11
= (5x² + 2x + 11) - (7 + 4x - 2x²)
Using distributive property:
= 5x² + 2x + 11 - 7 - 4x + 2x²
= 7x² - 2x + 4
The difference is 7x² - 2x + 4
Thus, the difference between the polynomials 5x² + 2x + 11 and 7 + 4x - 2x² is 7x² - 2x + 4 option (D)7x² - 2x + 4 is correct.
Learn more about Polynomial here:
#SPJ4
Perform the operation. Write the answer in standard form.
1. (6 − i) + (9 + 5i)
2. (7 + 3i) + (11 + 2i)
3. (12 + 4i) − (2 − 15i)
4. (3 − 7i) − (3 + 5i)
5. 7 − (2 − 3i) + 6i
6. −16 + (3 + 4i) − 4i
7. 3i(6 − 5i)
8. −2i(8 + 2i)
9. (−5 + i)(8 − 6i)
10. (3 − 6i)(−1 + 7i)
11. (2 + 5i)(2 − 5i)
12. (−3 − i)(−3 + I)
13. (4 + i) 2
14. (5 − 9i) 2
Thank you again <3
Answer:
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
Step-by-step explanation:
Standard form means to put the terms in order based on their exponent (x³ -> x² -> x -> constant)
1. (6 - i) + (9 + 5i)
2. (7 + 3i) + (11 + 2i)
3. (12 + 4i) - (2 - 15i)
4. (3 - 7i) - (3 + 5i)
5. 7 - (2 - 3i) + 6i
6. -16 + (3 + 4i) - 4i
7. 3i(6-5i)
8. -2i(8+2i)
9. (-5 + i)(8 - 6i)
10. (3 - 6i)(-1 + 7i)
11. (2 + 5i)(2 - 5i)
12. (-3 - i)(-3 + i)
13. (4 + i) * 2
14. (5 - 9i) * 2
:p when I first started answering this I thought the parentheses were being multiplied every time and did 100x more work .-.
Hope it helps <3 :D
The par value of each share is if the Waverly Brush Company issued 4,000 shares of common stock worth $200,000.00 total.
Further Explanation:
Given:
The Waverly Brush Company issued 4,000 shares.
The common stock worth is
Calculation:
The given worth of the common stock is
The total number of shares that Waverly Brush Company issued is 4,000.
The par value of each share can be calculated as follows,
The value of each share is
The par value of each share is if the Waverly Brush Company issued 4,000 shares of common stock worth $200,000.00 total.
Learn more:
Answer details:
Grade: High School
Subject: Mathematics
Chapter: Conic sections
Keywords: company, issue, 4000 share, shares, common stock, stock amount, par value share amount, worth, Waverly Brush Company, market value, par value.
Which could be the function graphed below?
b. Gas/Oil 120
c. Insurance 60
d. License/Registration 2
e. Taxes 5
f. Maintenance/Repair 50
what has she done wrong?
A: She budgeted more than the maximum recommended amount of money for transportation.
b: She has more money in the main category than she budgeted for in the subcategories.
c: She has more money in the subcategories than she budgeted for in the main category.
d: She budgeted less than the minimum recommended amount of money for transportation.
Answer:
c. She has more money in the subcategories than she budgeted for the main category
Explanation:
First, let's check the budget she set for the main category:
We are given that Maureen has net spendable income of $2,100.
The minimum amount she budgeted for transportation is 15% which can be calculated as follows:
Minimum budget for transportation = 15% * 2,100 = 0.15 * 2,100 = $315
Then, let's check her subcategories:
$150 for car payments, $120 for gas/oil, $60 for insurance, $2 for licence/registration, $5 taxes and $50 for maintenance/repair
This means that:
Minimum amount she will spend = 150 + 120 + 60 + 2 + 5 + 50 = $387
Now, let's compare:
Minimum budget set by Maureen is $315
Minimum amount she needs to spend on subcategories is $387
It is obvious that the minimum amount she needs is higher than the minimum budget she set for transportation, i.e., she has more money in subcategories than she budgeted in the main category.
This means that she needs either to increase her minimum budget for transportation or to lower the minimum amount she needs to spend.
Hope this helps :)
Answer:
Option C is correct.
Step-by-step explanation:
Given information is :
Net monthly spendable income = $2100
Transportation budget set up = $350 that lies between 15 to 20 percent of the net spendable.
Now adding her subcategories budget we get:
But Maureen has set $350 for this category. It clearly shows that the subcategories have more budget. So, either Maureen can increase her main category budget(this option is not given) or she can cut few of her subcategory budget to fall under $350.
Hence, Option c: She has more money in the subcategories than she budgeted for in the main category - is correct.