In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square?

Answers

Answer 1

Answer: f(x) = 4(x² - 6x + ___) + 20

completing the square.

a² + 2ab + b²

a² = x² = x * x
2ab = -6x = 2*x* -3
b² = -3² = 9

f(x) = 4(x² - 6x + 9) + 20
f(x) = 4x² - 24x + 36 + 20
f(x) = 4x² - 24x + 56

Answer 2

Answer:

Answer:

Step-by-step explanation:

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determine whether the given first-order differential equation is linear in the indicated dependent variable by matching it with the differential equation given in (7) in section 1.1, a1(x) dy dx a0(x)y

Answers

The given first-order differential equation is linear in the indicated dependent variable because it matches the standard form of a linear first-order differential equation, a1(x) dy/dx + a0(x)y = f(x).

First, let us review what a linear first-order differential equation is. Ais a differential equation that can be written in the form:

a1(x) dy/dx + a0(x)y = f(x)

Now, let us compare the given differential equation to the standard form of a linear first-order differential equation. The given differential equation is:

a1(x) dy/dx + a0(x)y

As we can see, the given differential equation matches the standard form of a linear first-order differential equation. Therefore, we can conclude that the given differential equation is linear in the indicated dependent variable.

In conclusion, the given first-order differential equation is linear in the indicated dependent variable because it matches the standard form of a linear first-order differential equation, a1(x) dy/dx + a0(x)y = f(x).

To know more about linear first-order differential equation, click the link below :

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A rectangle’s length is seven inches more than its width. If “w” is the width of the rectangle, in inches, what is the length of the rectangle, in inches?

Answers

so a rectangle's legnth is 7 times more than it's width

this means legnth=7 times width

l=legnth
l=7w
legnth is 7w inches

Consider the following two circles. Circle P with center (-1, 2) and radius 3 and circle Q with center (3, 4) radius 5. What sequence of transformations will carry circle P onto circle Q? Select all that apply.A. Dilation centered at Q, followed by reflection across the y-axis
B. Dilation centered at P, followed by reflection across the y-axis and then the line y = -x + 5
C. Translation (x,y) -> (x+4, y+2), followed by dilation centered at Q
D. Dilation (x+y) -> (3/5x, 3/5y), followed by dilation centered at P
E. Reflection over x-axis followed by rotation of 270 degrees

Answers

Answer:

B. Dilation centered at P, followed by reflection across the y-axis and then the line y = -x + 5

Step-by-step explanation:

Circle P.

Centerat (-1, 2).

Radius of 3.

Circle Q.

Center at (3, 4).

Radius of 5.

To carry one circle onto the other, their centers and radius must be the same.

So, circle P must be shifted from (-1, 2) to (3, 4), that means the translation is 4 units to the right side and two units upside, this is the first transformation.

The second transformation must be about stretching the circle P, from a radius of 3 to a radius of 5.

Therefore, the right answer is B.

Answer: Option b and Option c

True or False: Only like terms can be combined. A True B False

Answers

Answer:

True

Step-by-step explanation:

Like terms like 4x-3x the x term. is a like term

6-4x can be subtracted because they aren't the same.

High Hopes^^

Barry-

Answer:

i believe this false but im not positive

Determine two pairs of polar coordinates for the point (5, 5) with 0Á _ _ < 360Á

Answers

the polar coordinates are given by M(x, y), such tha x=rcos(teta), and y=rsin(teta), it was given M(5,5), so 5=rcos(teta) and 5=rsin(teta), the ratio gives us 5/5= cotan (teta), 1= cotan (teta), implies 1= tan(teta), so teta = Pi/4, let's find r
5=rsin(Pi/4)=r . sqrt(2)/2, so r =10/sqrt(2)=10sqrt(2)
finally the polar coordinates are (r, teta) = (10sqrt(2), Pi/4)

Find n.
35/49=5/n
n=_____

Answers

n = (5 * 49) / 35 = 7

Answer:

n = (5 * 49) / 35 = 7

your welcome

Step-by-step explanation:

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