Is 4y - 8 > 10 true?

From the second and third steps, we know that m∠TUV = m∠1 + m∠2. We also know that m∠XWV = m∠3 + m∠4. Since ∠TUV and ∠XMV both measure 90°, we can set their measures equal to each other:

m∠TUV = m∠XMV

or equivalently:

m∠1 + m∠2 = m∠3 + m∠4

Next, we can use the fact that ∠1 ≅ ∠3 to say that m∠1 = m∠3, while allows us to replace one with the other. Here, we'll replace m∠3 with m∠1:

m∠1 + m∠2 = m∠1 + m∠4

Subtracting m∠1 from either side:

m∠2 = m∠4, which implies that ∠2 ≅ ∠4, as we wanted to show.

By analyzing the asymptotes we can find the graph of the rational function. Also a graph is provided below.

Which graph represents the function?

We have the rational function:

f(x) = (2x)/(x^2 - 1).

First, you can see that we have two zeros on the denominator. One happens when x = 1 and the other when x = -1.

This means that the graph of this function will have two vertical asymptotes at these values. (four actually as we have one going to each end in each point).

With that description we can find the graph of the function, I will also post it so you can recognize it.

If you want to learn more about rational functions, you can read:

brainly.com/question/1851758

Answer:

Step-by-step explanation:

f(x) = 2 / (x^2 - 1) is better written as

                 2

f(x) = ------------------

         (x - 1)(x + 1)

This is undefined at x = -1 and x = 1; there are vertical asymptotes at x = -1 and x = 1.

The y-intercept is found by letting x = 0; we get

                 2

f(x) = ------------------ = -2    =>    (0, -2)

         (0 - 1)(0 + 1)

Please, next time, share the answer choices.  Thank you.

Answer:

x = 1

Step-by-step explanation:

You got it right but you need to solve for x

8x(8x + 6x) = 7(7+9)

8x(14x) = 7(16)

112x^2 = 112

   x^2 = 1

       x = 1

X=1 I’m pretty sure

Answer:

96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

Step-by-step explanation:

We are given that a survey was conducted to determine the average age at which college seniors hope to retire in a simple random sample of 101 seniors, 55 was the  average desired retirement age, with a standard deviation of 3.4 years.

Firstly, the Pivotal quantity for 96% confidence interval for the population mean is given by;

                         P.Q. =    ~

where, = sample average desired retirement age = 55 years

            = sample standard deviation = 3.4 years

            n = sample of seniors = 101

             = true mean retirement age of all college students

Here for constructing 96% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 96% confidence interval for the population mean, is ;

P(-2.114 < < 2.114) = 0.96  {As the critical value of t at 100 degree

                                               of freedom are -2.114 & 2.114 with P = 2%}  

P(-2.114 < < 2.114) = 0.96

P( < < ) = 0.96

P( < < ) = 0.96

96% confidence interval for = [ , ]

                                           = [ , ]

                                           = [54.30 , 55.70]

Therefore, 96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

Answer:

3/8

Step-by-step explanation:

choices:  6,7,8,9  total: 4

odd numbers: 7,9   total :2

P(odd number) = number of odds/ total

                          =2/4 = 1/2

Then we spin again

choices:  6,7,8,9  total: 4

number greater than 6: 7,8,9   total :3

P(odd number) = number greater than 6/ total

                          =3/4

P(odd, > 6) = P(odd, >6) = 1/2 *3/4 = 3/8