(6x3 – 4)(36x9 + 24x3 + 16)
(6x4 – 4)(36x8 + 24x4 + 16)
(6x4 – 4)(36x12 + 24x4 + 16)
Hello there!
This is a difference of cubes of the form:
(a^3-b^3) which always factors to (a-b)(a^2+ab+b^2)
So if you find the cube of each term you will have a and b for the factors above.
(216x^12)^(1/3)=6x^4 and 64^(1/3)=4 so
(6x^4-4)(36x^8+24x^4+16), So C. is the correct answer.