You added 3 3/4 cups of flour, 1 1/4 cups of oil, and 2 2/4 cups of water to a bowl for a recipe. How many cups did you combine in total?

Answers

Answer 1
Answer: 3 3/4 + 1 1/4 + 2 2/4 

3/4 + 1/4 + 2/4 = 1 1/2

3 + 1 + 2 + 1 1/2 = 7 1/2 cups total

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MATH HELP ASAP PLEASE

Answers


[3-(5-(7+1))^2]-5+3]

[3-(5-8)^2]-5+3]

[3-(-3)^2]-5+3]

[3+9]-5+3]

[12]-5+3]

12[-2]

12+2

14



[3-(5-(7+1))²]-5+3]
[3-(5-8)²]-5+3]
[3-(-3)²]-5+3]
[3-9]-5+3]
(-6)-5+3
(-11)+3
(-8)


A missile was fired from a submarine from 290 feet below sea level. If the missile reached a height of 17800 feet before exploding, what was the change in the altitude of the missile?

Answers

The answer is 17510 above sea level

Final answer:

The missile's change in altitude from the starting point 290 feet below sea level to the final position of height 17800 feet is calculated by subtracting the initial position from the final position, resulting in a change of 18090 feet.

Explanation:

The subject of this question falls under the domain of Mathematics, specifically involving numerical operations. It pertains to the calculation of change in altitude. Here's your step-by-step explanation:

1. The missile's starting point is 290 feet below sea level. We represent below sea level as a negative number, so the starting altitude of the missile is -290 feet.

2. The missile then ascended to a height of 17800 feet, which is above sea level and hence positive.

3. To find the change, we subtract the initial position from the final position: 17800 - (-290) = 17800 + 290 = 18090 feet.

So, the change in altitude of the missile is 18090 feet.

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Please help i cant figure this out

Answers

First work out the bracket: -1 2/3, make this into one fraction 
                                          a b/c = (ac+b)/c 
                                          ignore the negative for now, so 3+2= 5 so your                                             fraction is -5/3
Then multiply: 3/5 x -5/3 = -15/15 so your answer is -1
-1 2/3 = - (1*3+2/3)
          = - (3+2/3)
          = -5/3

Now lets multiply
= 3/5 * -5/3
= 3*-5 / 5*15
= -15/15
= -1

26 students in a hostel have provisions for 60 days if 10 more student are admitted to the hostel for how many days would the provisions be enough?​

Answers

Answer:

About 43 days

Step-by-step explanation:

Let's assume that the provisions in the hostel are consumed at a constant rate by each student per day. To find out how long the provisions would last with an additional 10 students, we need to consider the total number of students after the new admissions.

Initially, there are 26 students, and the provisions last for 60 days. Therefore, the total provision "student-days" is 26 students multiplied by 60 days, which equals 1560 student-days.

If 10 more students are admitted, the total number of students becomes 26 + 10 = 36 students.

To calculate how many days the provisions would last for 36 students, we divide the total provision "student-days" by the new total number of students:

1560 student-days / 36 students = 43.33 days (approximately)

Therefore, with 10 more students admitted, the provisions would be enough for approximately 43 days.

Answer:

44 days for the 36 students.

Step-by-step explanation:

Let's break down the information given:

Initially, there are 26 students in the hostel and provisions for 60 days. This means that the total "student-days" that the provisions can support is 26 students * 60 days = 1560 student-days.

Now, 10 more students are admitted to the hostel. So, the total number of students becomes 26 + 10 = 36 students.

We want to find out for how many days the provisions will be enough for these 36 students.

We can set up a proportion to solve this:

Initial student-days = New student-days

1560 student-days = 36 students * x days

Now solve for x:

x = 1560 student-days / 36 students

x = 43.33 days

Since you can't have a fraction of a day, we'll round up to the nearest whole day. Therefore, the provisions would be enough for approximately 44 days for the 36 students.

Pierce works at a tutoring center on the weekends. At the center, they have a large calculator to use for demonstration purposes that is a scale model of calculators available for the students to use. Each key on the student calculators is 14 millimeters wide, and each key on the demonstration calculator is 2.8 centimeters wide. If the student calculators are 252 millimeters tall, how tall is the demonstration calculator?

Answers

The height of the demonstration calculator is 504 millimeters.

To find the height of the demonstration calculator, we can use the ratio of the key widths between the student calculators and the demonstration calculator.

Let's first convert all measurements to the same unit for consistency. Since we need to find the height of the demonstration calculator, let's convert the width of the keys on the demonstration calculator to millimeters, which is the unit used for the height of the student calculator.

1 centimeter (cm) = 10 millimeters (mm)

Width of the key on the demonstration calculator =

= 2.8 cm x 10 mm/cm

= 28 mm

Now, we know the width of each key on the demonstration calculator is 28 millimeters.

We can use this information to find the height of the demonstration calculator.

The ratio of the width of the keys on the demonstration calculator to the width of the keys on the student calculator is:

= 28 mm (demonstration calculator) / 14 mm (student calculator)

Now, let's set up a proportion to find the height of the demonstration calculator (Hd):

Hd (demonstration calculator) / 252 mm (student calculator)

= 28 mm (demonstration calculator) / 14 mm (student calculator)

Hd / 252 = 28 / 14

Hd / 252 = 2

Hd = 2 x 252

Hd = 504 millimeters

So, the height of the demonstration calculator is 504 millimeters.

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Final answer:

The height of the large demonstration calculator is 50.4 cm, determined by converting measurements to the same units and using the scale factor between the student and demonstration calculators.

Explanation:

The question involves scale factor and unit conversion in mathematics. The scale factor between the student calculator buttons and the large demonstration calculator buttons is 2.8 cm (button size of large calculator) divided by 1.4 cm (button size of student calculator, which equates to 14 mm). Therefore, the scale factor is 2.

To find the height of the large calculator, we multiple the height of the student's calculator (252 mm or 25.2 cm) by the scale factor 2. Therefore, the height of the large demonstration calculator is 50.4 cm.

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Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length.A two column proof of the theorem is shown but the statement and reasons are not in correct order.

Answers

Reasons:
I) Segment DE is half the length of segment AC. By substitution

II) Segment DE is parallel to segment AC. Slopes of parallel lines are equal.

III) The coordinates of point D are (4, 5) and coordinates of point E are (5, 3) By the midpoint form