Factor the GCF: 4x^5 y^6 + 10x^2 y^3

Answers

Answer 1

Answer: $4x^(5) y^(6) + 10 x^(2) y^(3)$
Factor for the GCF
$2 x^(2) y^(3) ( 2 x^(3) y^(3) + 5)$

∴ $2 x^(2) y^(3)<span>$

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In the first 4 of 5 consecutive days, Martha delivered144, 152, 139, and 171 newspapers. How many
newspapers did Martha deliver on the fifth day, if the
average number of newspapers she delivered per day
during the five-day period was 155?
A. 154
B. 162
C. 169
D. 171
Given the number of newspapers delivered by
E. Martha on the first four days, she cannot average
155 per day for the five-day period.

Answers

Answer:

C. 169

Step-by-step explanation:

144+152+139+171+169=775

775÷5=155

Please help! (Will give brainliest answer and hearts) Thank you and have a nice day!

Answers

Answer:

B. 7- 10 years

Step-by-step explanation:

7 is the approximate time negative choices stay on. Things like paying the bill late and bankruptcies.

Answer:

Step-by-step explanation:

this will keep them in dept the longest

Both the leftmost digit and the rightmost digit of a four-digit numberN are equal to 1. When these digits are removed, the two-digit number
thus obtained is N ÷ 21. Find N.

Answers

$N=1000w+100x+10y+z\nw=z=1\nx,y\in\{0,1,2,\ldots,7,8,9\}\n10x+y=(N)/(21)\n10x+y=(1000w+100x+10y+z)/(21)\n10x+y=(1000+100x+10y+1)/(21)\n10x+y=(100x+10y+1001)/(21)\n210x+21y=100x+10y+1001\n110x+11y-1001=0\n10x+y-91=0\ny=-10x+91\n\n\hbox{The above equation meets the condition }x,y\in\{0,1,2,\ldots,7,8,9\}\n\hbox{only for } x=9:\ny=-10\cdot9+91\ny=-90+91\ny=1\n\n\hbox{Therefore:}\nN=1000\cdot1+100\cdot9+10\cdot1+1\nN=1000+900+10+1\nN=\boxed{1911}$