PHYSICS HIGH SCHOOL

John’s mass is 95.6 kg, and Barbara’s is 55.3 kg. He is standing on the x axis at xJ = +10.9 m, while she is standing on the x axis at xB = +2.50 m. They switch positions. How far and in which direction does their center of mass move as a result of the switch? Distance moved by center of mass =

Answers

Answer 1

Answer:

Answer:Shifted towards Left by distance of 2.243 m

Explanation:

Given

Mass of john $m_1=95.6 kg$

Mass of barbara $m_2=55.3 kg$

John is standing at $x=10.9 m$

Barbara is standing at $x=2.50 m$

$x_(com)=(m_1x_1+m_2x_2)/(m_1+m_2)$

$x_(com)=(95.6* 10.9+55.3* 2.5)/(95.6+55.3)$

$x_(com)=(1180.29)/(150.9)$

$x_(com)=7.821 m$

Now if they change their Position then

$x'_(com)=(95.6* 2.5+55.3* 10.9)/(95.6+55.3)$

$x'_(com)=(841.77)/(150.9)$

$x'_(com)=5.578$

Thus we can see that center of mass shifted towards left by a distance of $2.243 m$ because heavier is shifted towards left

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two vectors of same units have magnitude of 8 unit and 5 unit. what are the maximum and minimum magnitude of resultant that can be obtained with the two vectors?

Answers

Explanation:

Max will be when they are in the same direction: 8 + 5 = 13 units

Min will be when they are in opposite directions 8-5 = 3 units

What is a Vector and a scalar?

Answers

Scalars are quantities that are fully described by a magnitude (or numerical value) alone.
Vectors are quantities that are fully described by both a magnitude and a direction.

A student releases a block of mass m at the top of a slide of height h1. the block moves down the slide and off the end of the table of height h2, landing on the floor a horizontal distance d from the edge of the table. Friction and air resistance are negligible. The overall height H of the setup is determined by the height of the room. Therefore, if h1 is increased, h2 must decrease by the same amount so that the sum h1+h2 remains equal to H. The student wants to adjust h1 and h2 to make d as large as possible.A) 1) Without using equations, explain why making h1 very small would cause d to be small, even though

h2 would be very large?
2) Without using equations, explain why making h2 very small would cause d to be small, even though
h1 would be large

B) Derive an equation for d in terms of h1, h2, m, and physical constants as appropriate.

Answers

(A)

(1) The reason for making $h_(1)$ very small is due to smaller value of horizontal component of launch velocity.

(2) The reason for making $h_(2)$ very small is due to smaller value of time of flight.

(B) The distance (d) covered by the block is $2\sqrt{h_(1)h_(2)}$ .

Given data:

The mass of block is, m.

The height of table from the top of slide is, $h_(1)$ .

The height of table at the end of slide is, $h_(2)$ .

The height of room is, H.

(A)

(1)

If the launch velocity of the block is v, then its horizontal component is very small, due to which adjusting the height $h_(1)$ to be very small will cause the d to be small.

(2)

The height $h_(2)$ is dependent on the time of flight, and since the time of flight taken by the block to get to the floor is very less, therefore the block will not get sufficient time to accomplish its horizontal motion. That is why making $h_(2)$ very small will cause d to be smaller.

(B)

The expression for the distance covered by the block is,

$v=(d)/(t)\nd = v * t$ ..............................(1)

Here, v is the launch speed of block and t is the time of flight.

The launch speed is,

$v^(2)=u^2+2gh_(1)\nv=\sqrt{u^2+2gh_(1)}\nv=\sqrt{0^2+2gh_(1)}\nv=\sqrt{2gh_(1)}$

And the time of flight is,

$h_(2)=ut+(1)/(2)gt^(2)\nh_(2)=0 * t+(1)/(2)gt^(2)\nh_(2)=0+(1)/(2)gt^(2)\nt=\sqrt(2h_(2))/(g)$

Substituting the values in equation (1) as,

$d = v * t\nd = \sqrt{2gh_(1)}* \sqrt(2 h_(2))/(g)}\nd=2\sqrt{h_(1)h_(2)}$

Thus, the distance (d) covered by the block is $2\sqrt{h_(1)h_(2)}$ .

Learn more about the time of flight here:

brainly.com/question/17054420?referrer=searchResults

A1) The reason why making h₁ very small would cause d to be small is; Because the horizontal component of the launch velocity would be very small.

A2) The reason why making h₂very small would cause d to be small is;

Because the time of flight it will take the object to get to the floor would be very small and as a result, the object would not possess enough time to move horizontally before the vertical motion.

B) The equation for d in terms of h₁ and h₂ is;

d = 2√(h₁ × h₂)

A) 1) The reason why making h₁ very small would cause d to be small is because the horizontal component of the launch velocity would be very small.

A) 2) The reason why making h₂ very small would cause d to be small is because the time of flight it will take the object to get to the floor would be very small and as a result, the object would not possess enough time to move horizontally before the vertical motion.

B) Formula for Launch Velocity is;

V = √(2gh₁)

h₁ was used because the top of the slide from where the student released the block has a height of h₁.

Also, the time it takes to fall which is time of flight is given by the formula;

t = √(2h₂/g)

h₂ was used because the height of the table the object is on before falling is h₂.

Now, we know that d is distance from edge of the table and formula for distance with respect to speed and time is;

distance = speed × time

Thus;

d = √(2gh₁) × √(2h₂/g)

g will cancel out and this simplifies to give;

d = 2√(h₁ × h₂)

Read more at; brainly.com/question/20427663

Train is traveling at an initial velocity of 68.325m/s. After 23.75 seconds it speeds up to a final velocity of 79.32m/s. What is the train's acceleration during this time

Answers

So,

We know that:
$acceleration = ( final\ velocity\ -\ initial\ velocity)/(time)$

Plug in the values.
$acceleration = (79.32 m/s^(2)\ -\ 68.325m/s^(2))/(23.75 secs)$
$acceleration = (10.995m/s^(2) )/(23.75 secs)$
$acceleration = 0.4629 m/s^(2)$

Which uses the refractive properties of light to separate it into its different wavelengths? A.
white light from the surface of a mirror

B.
colored light as it travels from a solid medium to a liquid medium

C.
visible light as it passes through a lens

D.
sunlight through droplets of water in the atmosphere

Answers

A). No. A mirror doesn't separate light into its different wavelengths.

B). No. Light doesn't separate into its different wavelengths when it
goes, say, from glass into water.

C). No. When light goes through your glasses, it doesn't separate
into its different wavelengths.

D). Yes ! When sunlight shines into droplets of water in the atmosphere,
it comes out separated into its different wavelengths. When we see that
happening in the air in front of us, we call it a "rainbow".

You need to raise a heavy block by pulling it with a massless rope. You can either (a) pull the block straight up height h, or (b) pull it up a long, frictionless plane inclined at a 15∘ angle until its height has increased by h. Assume you will move the block at constant speed either way.

Answers

Final answer:

In both scenarios, the work done on the heavy block is the same, as it is determined by the change in the vertical height. However, pulling the block up the inclined plane may require less force because the work is distributed over a larger distance.

Explanation:

The subject of this question is based on the concept of work and energy in physics. When you pull the heavy block straight upwards (scenario a), the work done is equal to the force times the distance, or Work = mg*h, where m is the mass of the block, g is the acceleration due to gravity, and h is the height it needs to rise. For pulling the block up the inclined plane (scenario b), the work done still equals mg*h as the vertical distance it rises is the same.

This is because, according to the principle of work and energy, the work done on an object is equal to the change in its kinetic energy. Since the speed of the block remains constant in both scenarios, the kinetic energy does not change, meaning the work done on the block is the same in both scenarios.

However, pulling the block up the inclined plane may require less force because of the larger distance over which the work is done. But the overall work is the same in both cases.

Learn more about Work and Energy here:

brainly.com/question/16987255

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