MATHEMATICS MIDDLE SCHOOL

Solve the equation log4(x + 20) = 3
x=
DONE

Answers

Answer 1

Answer:

The value of x is 44.

Given

Equation; $\rm log4(x + 20) = 3$

The value of the x is determined by using the logarithmic properties following all the steps given below.

The value of x is;

$\rm log4(x + 20) = 3$

Taking log base 4 on both sides;

$\rm log4(x + 20) = 3\n\n(x+20) = 4^3\n\nx+20 = 4 * 4* 4\n\nx+20=64\n\nx=64-20\n\nx=44$

Hence, the value of x is 44.

To know more about Equation click the link given below.

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Answer 2

Answer:

Answer:

x = 44

Step-by-step explanation:

log4(x+20) = 3

4³ = x + 20

x + 20 = 64

x = 44

(Correctmeifiamwrong)

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I have a ring for each finger of both hands. I want to buy 4 more rings. How many rings will I have then?

Answers

you will

have 14 rings

you will have 14 rings, because you have ten fingers, and ten plus 4 is 14.

hope it helps.

The sum of two numbers is 100 and their difference is -20. What are the two numbers?

Answers

Answer:

x=40 and y= 60

Step-by-step explanation:

step:1

Let 'x' and 'y' are two numbers

given data the sum of two numbers is 100

x+y = 100......(1)

Given difference of two numbers are

x - y = -20 ......(2)

Step :2

solving the equation (1) and (2)

adding the equations (1) and (2)

x+y+x-y=100-20

cancelling 'y' terms are

2 x = 80

dividing "2" on both sides, we get

x = 40

Step :3

substitute x = 40 in equation (1)

x + y =100

40 + y = 100

subtracting "40" on both sides, we get

40 + y - 40 = 100 -40

y = 60

Final answer:-

The two numbers are x = 40 and y= 60

A camera manufacturer spends $1,800 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell for $18each. a. How many cameras must the company sell in one day to equal its daily costs? b. If the manufacturer can increase production by 50
cameras per day, what would their daily profit be?

Answers

Amount of money spent per day = $1800

Cost of overhead expenses per day for labor and materials = $9

Selling price of each camera = $18

a. Let us assume the number of cameras manufactured per day = x dollars

Then

Cost of cameras sold in 1 day = 18x

18x = 1800 + 9x

18x - 9x = 1800

9x = 1800

x = 200

From the above deduction, we can conclude that the number cameras sold per day is 200

b. Daily selling amount of 250 cameras = 250 * 18

= 4500 dollars

Daily manufacturing price of 250 cameras = 1800 + (9 * 250)

= 4050 dollars

Then

Daily profit = 4500 - 4050

= 450 dollars

How do you figure this out

Answers

I'm not sure if you're looking for a percentage or a decimal, but to find the answer you just need to do 160 ÷ 16 = 10. This means that, if you want it as a fraction, the answer is 1/10, and if you want it as a percentage, the answer is 10%. I hope this helps!

In angle FKR which side is included between angle f and angle r? A. Angle K
B. line segment FK
C. Line segments AR
D. Line segment RF