Answer:
Step-by-step explanation:
Distribute 2(x+2):
2(x) + 2(2) = 2x + 2
Use the FOIL method to multiply (2x + 2)(x+6)
(2x + 2)(x+6)
2x(x) = 2
2x(6) = 12x
2(x) = 2x
2(6) = 12
2 + 12x + 2x + 12 = 2 + 14x + 12
Graph the following equation on a graphing calculator, and then you should know how to graph it on paper.
1 min = 60 sec
On a coordinate plane, a parabola opens down. It goes through (negative 4, 0), has a vertex at (negative 1. 75, 6.2), and goes through (1, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 1, 0), has a vertex at (1. 75, negative 6.2), and goes through (4, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 4, 0), has a vertex at (negative 1. 75, negative 6.2), and goes through (1, 0).
Answer:
None of the above
Step-by-step explanation:
See the attachment for x-intercepts and vertex coordinates. These coordinates do not match any of the answer choices.
___
The closest choice is the last one. It has the direction of opening and the intercepts correct, but the vertex coordinates wrong.
We can write the graph of f(x) = (x - 1)(x + 4) as, "On a coordinate plane, a parabola opens up. It goes through (-4, 0), has a vertex at (-1.5, -6.25), and goes through (1, 0)."
A parabola is a plane curve created by a moving point whose distance from a stationary point equals its distance from a fixed-line.
In the question, we are given an equation of f(x) = (x - 1)(x + 4), and are asked to identify its graph.
The given equation is of a parabola in the intercept form f(x) = a(x - p)(x - q), which opens up if a > 0 and opens down if a < 0, and which has a vertex at the point , and passes through the point (p, 0) and (q, 0).
Comparing the equation f(x) = (x - 1)(x + 4) to f(x) = a(x - p)(x - q), we get
a = 1, p = 1, q = -4.
Since, a > 0 (a = 1), we can say that it opens up.
Now, we calculate (p + q)/2 = (1 - 4)/2 = -1.5
f((p + q)/2) = f(1.5) = (-1.5 - 1)(-1.5 + 4) = (-2.5)(2.5) = -6.25.
Thus, the vertex is at point (-1.5, -6.25).
Also, the equation passes through the points (-4, 0) and (1, 0).
∴ We can write the graph of f(x) = (x - 1)(x + 4) as, "On a coordinate plane, a parabola opens up. It goes through (-4, 0), has a vertex at (-1.5, -6.25), and goes through (1, 0)."
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