Which of the following changes would make a heat engine less efficient

Answers

Answer 1
Answer: A heat engine would be less efficient due to many factors 
For instance, a heat engine is more efficient when it uses in cold weather because there is a greater temperature difference ( Carnot Efficient )
A heat engine could be less efficient because of friction
Hope it helps I am a beginner

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a transformer with a turns ratio (secondary/primary) of 1:10 is used to step down the voltage from a 120-v wall socket to be used in a battery recharging unit. What is the voltage supplied to the recharger?

Answers

The voltage ratio of a transformer is nominally equal to the turns ratio.

If you connect 120 volts AC to one side of the 1:10 transformer, you'll
get 12 volts out of the other side if you connected it up the correct way,
or 1200 volts if you connected things up backwards.

Note that it has to be AC.  If the input to a transformer is DC, then the
output is always smoke.

Answer:

the answer on edge is 48

Explanation:

     

Which of the following is not a manmade cause of global warming?

Answers

Well if climate change is one of the options then that would be it

Erica needed to practice dribbling the ball up and down the length of the court. She divided to do it 10 times. How far did she dribble?

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Answer:

ok

Explanation:

what is the length of the court. you need the length to answer the question

While sitting in your car by the side of a country road, you see your friend, who happens to have an identical car with an identical horn, approaching you. You blow your horn, which has a frequency of 260 Hz; your friend begins to blow his horn as well, and you hear a beat frequency of 6.0Hz .How fast is your friend approaching you?

Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

         v_s =7.74\ m/s

Explanation:

given,

Speed of sound = 343 m/s

frequency of horn = 260 Hz

the friend is approaching, the frequency is increased by the Doppler Effect. The frequency is 266 Hz

using formula

         f' = (v)/(v-v_s)f_0

         266= (343)/(343 - v_s)(260)

         1.023= (343)/(343 - v_s)

         343 - v_s = 335.26

         v_s =7.74\ m/s

the speed of friends approaching is equal to v_s =7.74\ m/s

Conservation of energy - questions

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