Write a Multiplication Expression using the variable s to represent the area of a Square

Answers

Answer 1

Answer: SxS = area

S= side

In other words, the area of a square is s^2

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Need help finding the equation if a circle expanded form

Answers

The formula would be -(y-1)^2-(x+3)^2=-1

What is the value of x in the equation 2x+3y=35 when y=6

Answers

Answer:

x = 17/2 or x = 8.5 decimal

Step-by-step explanation:

Solve for x:

2 x = 17

Divide both sides of 2 x = 17 by 2:

(2 x)/2 = 17/2

2/2 = 1:

Answer: x = 17/2 or x =8.5 decimal

Which equation can you use to solve for x

Answers

As for a specific equation, I could not say. However, I can tell you how to find x!

The first thing to remember is that a straight line has a 180 degree angle.

You see on the bottom side that we have a 146 degree angle. Now look at the top side. Look closely, and you will see that the two sides are actually identical!

Don't see it? Look at the line on top between x and 56, and imagine it is not there. You see that we actually have the same 146 degree angle, just flipped right side up!

However, this angle does not say 146, but makes an extra line between them with x and 56. This means that x + 56 equals 146!

So we can find x by subtracting 56, from 146, which is... 90!

When making a function table, which values do the x-coordinate and y-coordinate represent?

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Hey! The answer is input and output

I need help on this question

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500(.25)=125 is the answer

What is the value of r in the equation?
-1.5(4-r)=-12
0 -6
-4
4
06

Answers

Answer:

r = -4

Step-by-step explanation:

-1.5(4-r)=-12

Divide each side by -1.5

-1.5/-1.5(4-r)=-12/-1.5

(4-r)=8

Subtract 4 from each side

4-r-4 = 8-4

-r = 4

Divide each side by -1

r = -4

Answer:

r = -4

Step-by-step explanation: I hope it helps :)

$-1.5(4-r)=-12\n\n\mathrm{Multiply\:both\:sides\:by\:}10\n\n-1.5\left(4-r\right)\cdot \:10=-12\cdot \:10\n\n= -15\left(4-r\right)=-120\n\n\mathrm{Divide\:both\:sides\:by\:}-15\n\n(-15\left(4-r\right))/(-15)=(-120)/(-15)\n\n4-r=8\n\n\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\n\n4-r-4=8-4\n\n-r=4\n\n\mathrm{Divide\:both\:sides\:by\:}-1\n\n(-r)/(-1)=(4)/(-1)\n\nr=-4$

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