The element that has maximum density at STP is copper.
Further explanation:
The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:
1. Intensive properties:
These are the properties that depend on the nature of the substance. These don't depend on the size of the system. Their values remain unaltered even if the system is further divided into a number of subsystems. Temperature, refractive index, concentration, pressure, and density are some of the examples of intensive properties.
2. Extensive properties:
These are the properties that depend on the amount of the substance. These are additive in nature when a single system is divided into many subsystems. Mass, energy, size, weight, and length are some of the examples of extensive properties.
Density is a characteristic property of the substance. It is defined as the mass per unit volume. It is generally represented by .
The formula to calculate the density of the liquid is,
Standard Temperature and Pressure is denoted as STP and the volume of 1 mole of gas at STP is 22.4 litres.
The volume is constant and therefore density is directly related to mass.
Among the given elements copper has the highest molar mass and that is . Therefore the element that has maximum density at STP is copper.
Learn more:
1. Calculation of density: brainly.com/question/778841
2. Determine how many moles of water produce: brainly.com/question/1405182
Answer details:
Grade: Middle School
Subject: Chemistry
Chapter: Density
Keywords: density, mass, volume, STP, intensive, extensive, characteristic property, element, copper, chlorine, calcium, and carbon.
A. What is the limiting reagent?
B. How many grams of the excess reactant remains?
C. How many grams of each product is formed?
D. If 12 grams of NaNO3 actually formed in the reaction, what is the percent yield of this reaction?
Answer:
Explanation:
Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)
MM for each compound -
Pb(NO3): 207 + 14x2 + 16x3x2 = 331
PI2: 207 + 127x2 = 461
NaI: 23 + 127 = 150
NaNO3: 23 + 14 + 16x3 = 85
Moles of Pb(NO3)2 = 50/331 = 0.15
Moles of NaI = 30/150 = 0.2
Ratio of moles is 1:2
So NaI is limiting
Limited to 0.2/2 = 0.1 mole of Pb(NO3)2
Excess = 0.15 - 0.1 = 0.05 mole
Mass remains = 0.05x331 = 16.55 grams
Moles of NaNO3 formed = Moles of NaI reacted = 0.2
Mass = 0.2x85 = 17 grams
Moles of PbI2 formed = Moles of Pb(NO3)2 reacted = 0.1
Mass = 0.1x461 = 46.1 grams
If 12 grams of NaNO3 actually formed in the reaction,
percent yield = 12/17x100% = 70.6%
Answer:
Explanation:
Moles of Pb(NO3)2 = mass/molecular mass
= 50.0 grams/(207.20*1 + 14.01*2 + 16*6)
= 50.0 grams/331.22
= 0.15 moles
Moles of NaI
= 30/(22.99+126.9)
= 30/149.89
= 0.2 Moles
A. NaI is less 2x Pb(NO3)2 so NaI is the limiting reagent.
B. The ratio is 1 to 2 so there is 0.15 - 0.2/2 = 0.05 mole
or 16.78 grams of Pb(NO3)2 left.
C. As NaI is limiting, only 0.2 Moles of NaNO3 is formed.
Mass = Moles * Molecular Mass
Molecular Mass of NaNO3 can be calculated as:
Na - 22.99
N - 14.01
O - 3(16) = 48
23+14+48 = 85gram / mole
Thus, Mass = 0.2*85 = 17 gram of NaNO3
Mass is conserved in a chemical reaction.
Mass of PbI2 can be calculated as:
50+30-16.78-17
= 46.3 gram of PbI2
Mass =
12.75
Thus, 12.75g of Sodium Nitrate can be formed
if a sample of magnesium has a mass of 60 g, how many moles of magnesium does the sample contain
Answer : The moles of magnesium will be, 2.5 moles
Explanation : Given,
Mass of magnesium = 60 g
Molar mass of magnesium = 24 g/mole
Formula used :
Now put all the given values in this formula, we get the moles of magnesium.
Therefore, the moles of magnesium will be, 2.5 moles
Answer:
28 grams
Explanation:
Molar mass of Nitrogen = 14 u
Mass = Mole * Molar Mass
= 2 * 14
= 28 g
There are approximately of silver in the 100 mL silver bar.
To determine the number of atoms in a silver bar, you can follow these steps:
Calculate the mass of the silver bar:
Mass (g) = Volume (mL) x Density (g/mL)
Mass = 100 mL x 10.5 g/mL = 1050 g
Calculate the molar mass of silver (Ag):
The molar mass of silver (Ag) is approximately 107.87 g/mol.
Calculate the number of moles of silver in the bar:
Moles = Mass (g) / Molar Mass (g/mol)
Moles = 1050 g / 107.87 g/mol ≈ 9.73 moles
Calculate Avogadro's number:
Avogadro's number is approximately
Calculate the number of silver atoms in the bar:
Number of atoms = Moles x Avogadro's number
Number of atoms =
Thus, there are approximately of silver in the 100 mL silver bar.
For more such questions on silver:
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