Question 2 i need help on
question 2 i need help on - 1

Answers

Answer 1
Answer: Number 4 a rectangular dodecagon
Answer 2
Answer: For question two its number 4 

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1. The price of gas has increased over time due to inflation and other factors. Assume that the equation y = 1.26(1.10) x represents the price of gas for the years after 2000.
Using this equation, fill in the following T-table for the years 2000, 2002, 2004, 2006, 2008, and 2010. Use X = 0, 2, 4, 6, 8, and 10 to represent these years (the number of years after 2000). Round your answers to the nearest cent.

Answers

Answer:

Step-by-step explanation:

The equation representing the price of gas for the years after 2000 is expressed as

y = 1.26(1.10)^x

Where x = 0, 2, 4, 6, 8, and 10 represent these years : 2000, 2002, 2004, 2006, 2008, and 2010, the table would be

1) x = 0(2000)

y = 1.26(1.10)^0

y = 1.3

2) x = 2(2002)

y = 1.26(1.10)^2

y = 1.5

3) x = 4(2004)

y = 1.26(1.10)^4

y = 1.8

4) x = 6(2004)

y = 1.26(1.10)^6

y = 2.2

5) x = 8(2006)

y = 1.26(1.10)^8

y = 2.7

6) x = 10(2008)

y = 1.26(1.10)^10

y = 3.3

Use elimination to solve each system of equations.please help me im dying


2x - y = -1

3x - 2y = 1

Answers

Answer:

x=-3

Y=-5

Step-by-step explanation:

2x-y=-1 ×2

3x-2y=1. ×1

4x-2y= -2

3x-2y=1

eliminate y by subtracting

Which system of inequalities is shown below in the graph

Answers

show the graph to me.

There isn't a graph so i cant really answer

PLS HELP FIRST CORRECT ANSWER GETS BRAINLIEST !! A pile of tailings from a gold dredge is in the shape of a cone. The diameter of the base is 34 feet and the height is 16 feet. Approximately, how many cubic feet of gravel is in the pile? Use π = 3.14.A. 14,527 ft³
B. 285 ft³
C. 4,840 ft³
D. 6,032 ft³

Answers

The volume of the cone is 4840 cubic ft if the diameter of the base is 34 feet and the height is 16 feet option (C) is correct.

What is a cone?

It is defined as a three-dimensional shape in which the base is a circular shape and the diameter of the circle decreases as we move from the circular base to the vertex.

\rm  V=\pi r^2(h)/(3)

Volume can be defined as a three-dimensional space enclosed by an object or thing.

It is given that:

A pile of tailings from a gold dredge is in the shape of a cone.

The diameter of the base is 34 feet and the height is 16 feet.

As we know,

The volume of the cone is given by:

\rm  V=\pi r^2(h)/(3)

r = 34/2 = 17 ft

h = 16 feet

Plug the above values in the formula:

\rm  V=\pi (17)^2(16)/(3)

After solving:

V = 1541.33π cubic feet

Take π = 3.14

V = 1541.33(3.14) cubic feet

V = 4839.78 ≈ 4840 cubic ft

Thus, the volume of the cone is 4840 cubic ft if the diameter of the base is 34 feet and the height is 16 feet option (C) is correct.

Learn more about the cone here:

brainly.com/question/16394302

#SPJ5

Answer:

C: V=4840 (2 s.f.)

Step-by-step explanation:

The formula for the volume of a cone is:

V= (1)/(3) \pi r^2h

Therefore,

V=(1)/(3)* 3.14*((34)/(2))^2* 16\n\nV=4840 (2 s.f.)

problems involving ratio and propotion in real life. tete and tuke share P8900 in the ratio 2:3. how much does each get respective?​

Answers

Answer:

Step-by-step explanation:

Tete : Tuke\n2  : 3\nTotal-Amount = P8900\n2+3 = 5\nTete = (2)/(5) * 8900\nTete = P3560\n\nTuke = (3)/(5) *8900\nTuke = P5340

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

Answers

Quadratic equation is the polynomial equation whose highest power of the variable is two. The standard form of the given equation is,

x^2-16x-36&=0

The factor roots of the equation are -2 and 8.

Given information-

The quadratic equation given in the problem is,

x^2 -6 = 16x + 30

Quadratic equation-

Quadratic equation is the polynomial equation whose highest power of the variable is two. Quadratic equation is the equation which involves only one unknown variable.

The standard form of the quadratic equitation can be given as,

ax^2+bx+c=0

Here, a,b and c are the known variables and x is the unknown.

Convert the given equation in the standard form,

x^2 -6 = 16x + 30

Equate the above equation to the zero and bring all the variables and constant one side,

x^2-6-16x-30=0\n

Arrange the equation with the power of x,

\begin{aligned}\n x^2-16x-30-6&=0\n x^2-16x-36&=0\n \end

Factored the above equation,

\begin{aligned}\nx^2-16x-36&=0\nx^2+2x-18x-36&=0\nx(x+2)-18(x+2)&=0\n(x+2)(x-18)&=0\n\end

equate them to the zero we get,

x=-2, 18

Hence the standard form of the given equation is,

x^2-16x-36&=0

The factor roots of the equation are -2 and 8.

Learn more about the quadratic equation here;

brainly.com/question/17177510

Answer:

(x-18) (x+2) =0

and

x=-2 or x=18