Answer:
16.27 g of CaCO3 are produced upon reaction of 45 g CaCN2 and 45 g of H2O.
Explanation:
Ca(CN)2 + 3H2O → CaCO3 + 2 NH3
First of all, let's find out the limiting reactant.
Molar mass Ca(CN)2.
Molar mass H2O: 18 g/m
Moles of Ca(CN)2: mass / molar mass
45 g / 92.08 g/m = 0.488 moles
Moles of H2O: mass / molar mass
45g / 18g/m = 2.50 moles
This is my rule of three
1 mol of Ca(CN)2 needs 3 moles of H2O
2.5 moles of Ca(CN)2 needs (2.5 . 3) / 1 = 7.5 moles
I need 7.5 moles of water, but I only have 0.488. Obviously water is the limiting reactant; now we can work on it.
3 moles of water __ makes __ 1 mol of CaCO3
0.488 moles of water __ makes ___ (0.488 . 1) / 3 = 0.163 moles
Molar mass CaCO3 = 100.08 g/m
Molar mass . moles = mass
100.08 g/m . 0.163 moles = 16.27 g
Answer:
terremotos
Explanation:
Answer:
BaCl2(aq) + K2CrO4(aq) = BaCrO4(s) + 2KCl(aq).
Explanation:
B. CO2
C. H2O
D. CH4
Answer : The correct option is, (C)
Explanation :
Formula used:
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
First we have to determine the hybridization of the following molecules.
(a)
This is diatomic molecule and diatomic molecules always form linear shape.
(b)
The number of electrons is 2 that means the hybridization will be and the electronic geometry of the molecule will be linear.
(c)
The number of electrons is 4 that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral.
But as there are two atoms around the central oxygen atom, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent.
(d)
The number of electrons is 4 that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral.
Hence, the molecule has bent structure will be,