An unbalanced force of 40. newtons keeps a5.0-kilogram object traveling in a circle of radius
2.0 meters. What is the speed of the object?
(1) 8.0 m/s (3) 16 m/s
(2) 2.0 m/s (4) 4.0 m/s

Answers

Answer 1
Answer: This can be answered using the formula of centripetal force. In the given problem, the centripetal force (40 N), mass (5 kg), radius (2 m) are all named, except for the speed. The formula is shown below:

F = mv^2 / r

Substituting the given values:

40 N = 5kg(v^2) / 2
80 = 5 * v^2
v^2 = 16
v = 4

Therefore, the correct answer is 4.0 m/s (4).

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Answers

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Answers

Answer:

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Answers

I don't understand the question. 
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Answers

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Answers

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Answers

Answer:  B    

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