Given:
128g sample ofwater
2808J of heatenergy
Required:
Change intemperature
Solution:
This can be solvedthrough the equation H = mCpTwhere H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
The specific heatof the water is 4.18 J/g-K
Plugging in thevalues into the equation
H = mCpT
2808J = (128g)(4.18 J/g-K) T
T= 5.25 K
B.)gas
C.)liquid
Answer:
solid
Explanation:
because solid has a definite shape and volume
Answer:
Liquid
Explanation:
This is because the intermolecular forces of attraction are strong enough to hold the molecules together but not so strong as to fix them into definite positions (as in solids). Instead, they possess fluidity and hence no definite shape.
the answer is 5.6 !!
Answer:
P = 4.92 atm
Explanation:
Given data:
Number of mole of oxygen = 0.352 mol
Volume of gas = 1.75 L
Temperature = 25°C
Pressure exerted by gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
25+273 = 298 K
P × 1.75 L = 0.352 mol × 0.0821 atm.L/ mol.K ×298 K
P = 8.61 atm.L / 1.75 L
P = 4.92 atm
O2
H2
NH3
NO
SO2
1. 44 grams
2. KCIO3
3. the third one
hope this helps :)