Ans: Volume of stock H2SO4 required = 6.94 ml
Given:
Concentration of stock H2SO4 solution M1 = 18.0 M
Concentration of the final H2SO4 solution needed M2 = 2.50 M
Final volume of H2SO4 needed, V2 = 50.0 ml
To determine:
Volume of stock needed, V1
Explanation:
Use the dilution relation:
Hello!
In a school’s laboratory, students require 50.0 mL of 2.50 M H2SO4 for an experiment, but the only available stock solution of the acid has a concentration of 18.0 M. What volume of the stock solution would they use to make the required solution?
We have the following data:
M1 (initial molarity) = 2.50 M (or mol/L)
V1 (initial volume) = 50.0 mL → 0.05 L
M2 (final molarity) = 18.0 M (or mol/L)
V2 (final volume) = ? (in mL)
Let's use the formula of dilution and molarity, so we have:
Answer:
The volume is approximately 6.94 mL
_______________________________
Answer:
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Explanation:
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This componet can be incorporated to produce an energy efficient and long lasting lighting device. So, Ron should use a Light Emitting Diode (LED) lighting device.
b. acetyl CoA formation
c. electron transport chain
d. citric acid cycle
Answer:
The answer to this problem is c
Explanation:
(2) 0.10 M K2SO4(aq)
(3) 0.10 M K3PO4(aq)
(4) 0.10 M KNO3(aq)
It is dense.
B.
It has a melting point.
C.
It is hard to bend.
D.
It becomes rusted.
the answer is d.it becomes rusted