Answer:
It’s 2)
Explanation:
A. ClAl3.
B. Cl3Al.
C. AlCl3.
D. Al3Cl.
AICI3
which is choice c.
Aluminium chloride
Chemical compound
DescriptionAluminium chloride is the main compound of aluminium and chlorine. It is white, but samples are often contaminated with iron(III) chloride, giving it a yellow color. The solid has a low melting and boiling point. Wikipedia
IUPAC ID: aluminium chloride
Molar mass: 133.34 g/mol
Soluble in: Water
Related Lewis acids: Iron(III) chloride; Boron trifluoride
Heat capacity (C): 91.1 J/mol·K
Other names: aluminium(III) chloride; aluminum trichloride
The name of the chemical compound Pb3N4 is Lead (IV) Nitride. The number of atoms of each element in the compound is represented by the subscript numbers, and the '-ide' suffix is used for the non-metal (Nitrogen). The Roman numeral indicates the oxidation state of Lead.
The chemical formula Pb3N4 corresponds to a compound made up of Lead (Pb) and Nitrogen (N). The subscript numbers (3 and 4) denote the number of atoms from each element present in the compound. Considering that Lead is a metal and Nitrogen is a non-metal, we use the '-ide' suffix for the non-metal in the name of the compound. Therefore, the name of Pb3N4 is Lead (IV) Nitride. The Roman numeral (IV) indicates the oxidation state of Lead in the compound.
Answer:
[BrCl] = 0,13M
Explanation:
For the reaction:
Br₂(g) + Cl₂(g) ⇄ 2BrCl
kc = [BrCl]²/[Br₂] [Cl₂] (1)
If initial [Br₂] and [Cl₂] are 0,25mol/3,0L=0,083M and 0,55mol/3,0L=0,18M, the concentrations in equilibrium are:
[Br₂] = 0,083M - x
[Cl₂] = 0,18M - x
[BrCl] = 2x
Replacing in (1)
7 = (2x)²/ (0,083 - x)(0,18 - x)
7 = 4x²/ x²- 0,263x + 0,01494
7x² - 1,841x + 0,10458 = 4x²
3x² - 1,841x + 0,10458 = 0
Solving for x:
x = 0,0633. As [BrCl] = 2x. [BrCl] = 0,13M
I hope it helps!
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