What is an isobar?a. a unit of measurement for air pressure
b. a line along which air pressure is constant
c. a region in which the weather is not changing
d. a symbol on a weather map showing wind direction

Answers

Answer 1
Answer:

Answer:

B.a line along which air pressure is constant

Explanation:

i took the quiz and got it right


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Cucumbers are sold for 3.50 QAR per kilogram. If you purchase 0.7kg of cucumbers how much will it cost? a. 5.95QAR b. 4.20 QAR c. 2.80QAR d. 2.45QAR

The point on a graph where X and Y values meet is called A. the axis.
B. the origin.
C. the starting line.
D. an intersection point.

Answers

The point where x and y values meet is called the origin.

the point where they meet at is called the origin

CONSIDER A TRAIN WHICH CAN ACCELERATION OF 20CM/SEC AND SLOW DOWN WITH ACCELERATION OF 100 CM/SEC FIND THE MINIMUM TIME FOR TRAIN TO TRAVEL BETWEEN THE STATIONS 2.7 KM PER A PART

Answers

The train accelerates at the rate of 20 for some time, until it's just exactly
time to put on the brakes, decelerate at the rate of 100, and come to a
screeching stop after a total distance of exactly 2.7 km.

The speed it reaches while accelerating is exactly the speed it starts decelerating from.

Speed reached while accelerating = (acceleration-1) (Time-1) = .2 time-1

Speed started from to slow down = (acceleration-2) (Time-2) = 1 time-2  

The speeds are equal.
.2 time-1 = 1 time-2
time-1 = 5 x time-2

It spends 5 times as long speeding up as it spends slowing down.

The distance it covers speeding up = 1/2 A (5T)-squared
= 0.1 x 25 T-squared = 2.5 T-squared.

The distance it covers slowing down = 1/2 A (T-squared)
= 0.5 T-squared.

Total distance = 2,700 meters.
(2.5 + .5) T-squared = 2,700
T-squared = 2700/3 = 900

T = 30 seconds

The train speeds up for 150 seconds, reaching a speed of 30 meters per sec
and covering 2,250 meters. 
It then slows down for 30 seconds, covering 450 meters.

Total time = 180 sec = 3 minutes, minimum.

Observation:
This solution is worth more than 5 points.
This can be done by hit and trial easily.

Considering train accelerate for 13000s and deaccelerate for 1000s
so total distance covered is = 20cm/s * 13000s + 100cm/s*100s
= (260000 + 10000 )cm
= 270000cm
= 2.7km

So total time taken is - 13100 seconds

A machine uses a force of 200 newtons to do 20,000 joules of work in 20 seconds. Find the distance the object moved and the power of the machine.

Answers

work=force * distance
20,000 joules= 200 newtons * d 
divide both sides by 200

100= distance

A proton has a charge of 1.6 × 10-19 C and a mass of 1.67 × 10-27 kg. A proton moves with velocity 1.8 × 105 m/s in the z-direction. A magnetic field with B = 2.1 × 10-1 T points in the y-direction. Find the magnitude and direction of the magnetic force on the proton.What is the angle between the proton’s velocity and the magnetic field?
45°
90°
180°
50°

I'll report you if you don't actually help. I'd like an actual explanation, please.

Answers

Hey

So first we need to know what the direction of the force is, using your right hand rule point your right hand in the direction of the velocity. You're saying its the z direction, not telling me whether it's into the page or out? Since its a positive z im assuming its coming out. The magnetic field is pushing it upwards, so the force is going in the negative x direction.

The force of a magnetic field is

F = Qv X B

What's weird is that you don't need mass in this equation. Actually you don't even need the formula, its telling you that they're all going in perpendicar directions. the answer is 90 degrees.

Now if you want to know the F just multiply the charge, velocity and magnetic field .

F = GVB

F = 6.048 E -15

Answer : 90 degrees, sin(90) = 1

Final answer:

To find the magnitude and direction of the magnetic force on a proton moving in a magnetic field, you can use the equation F = qvBsinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field. The magnitude of the magnetic force can be calculated using the equation, and its direction can be determined using the right-hand rule. In this case, the angle between the proton's velocity and the magnetic field is 90°.

Explanation:

To determine the magnitude of the magnetic force on the proton, we need to use the equation F = qvBsinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field.

Plugging in the values, we have F = (1.6 × 10-19 C)(1.8 × 105 m/s)(2.1 × 10-1 T)sinθ.

To find the angle θ, we can use the fact that the force is perpendicular to both the velocity and the magnetic field, which means that sinθ = 1.

Therefore, the magnitude of the magnetic force on the proton is F = (1.6 × 10-19 C)(1.8 × 105 m/s)(2.1 × 10-1 T) = 6.048 × 10-14 N. The direction of the magnetic force is given by the right-hand rule, which shows that the force is perpendicular to both the velocity and the magnetic field, pointing in the positive x-direction.

The angle between the proton's velocity and the magnetic field is 90°.

Learn more about magnetic force on a charged particle here:

brainly.com/question/19525738

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Convert 1 mm of Hg into pascal

Answers

1 millimeter of mercury is 133.322 pascals

When two forces act on an object in the same direction the resultant force is equal to

Answers

When two (or more) forces act on an object, all in the same direction,
the resultant force is equal to the sum of the individual forces.

That's a big part of the reason why, when you're pushing a car, you
ask somebody else to come push it with you, in the same direction.