0.038 g He
From the question we are given;
Volume of the flask, V = 250 mL
Pressure of He, P = 700 torr
Temperature, T = 25°C, but K = 273 + °C
= 298 K
We are required to calculate the mass of Helium present in the flask.
We are going to use the ideal gas equation to first get the number of moles of He present in the flask.
Ideal gas equation, PV = nRT, where n is the number of moles and R is the ideal gas constant.
In this case, R will be 62.364 L.Torr/mol.K, since the pressure is in torr.
Rearranging the equation;
n = PV ÷ RT
= (0.25 L × 700 torr) ÷ (62.364 × 298 K)
= 0.00942 moles
With the number of moles, we can calculate the mass of He.
Mass = Number of moles × molar mass
Molar mass of He = 4.0 g/mol
Therefore,
Mass = 0.00942 moles × 4.0 g/mol
= 0.03768 g
= 0.038 g He
Answer:
The material we are talking about would be serpentine.
Explanation:
This material is available in two colours green or white and it has a hardness that amounts to 2.5. This material has a luster that is nonmetallic and more of waxy in nature.
This feature becomes Satiny when Nature of is material is Fibrous. This material is used as an insulating material against electricity as well as heat. The property of this mineral is very close to asbestos and is used when prevention from heat and electricity is required.
Answer:
Halite
Explanation:
Halite is the mineral which is called as Rock salt shows cubic cleavage
Halite forms clear transparent crystals with perfect cubic cleavage. Halite is Table salt, the salt is an array of small cubic fragments, the result of halite’s crystal structure and perfect cubic cleavage
Cubic cleavage can be produced by breaking the sample. Halite is one of the few common minerals that, when broken into small fragments, will readily dissolve in water.
Answer:-64
Explanation: