MATHEMATICS HIGH SCHOOL

2. Which expression is in simplified form for the given expression and states the correct variable restriction? U^2-4 over (u-6)(u-2)A. u + 2 over u - 6, U - 6
B. 1 over 2u + 12, u - 6
C. 1 over u - 3, u - 3
D. u + 2 over u - 6, u2, u6
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3. Multiply. 5a3 . 2a over ab . 35

A. 2a3 over 7
B. a3 over 7b
C. 2a2 over 7
D. 2a3 over 7b
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4. Multiply. (a-4)(a+3) . 2a3 over a2-4a . (a+3)(a-1)

A. 2 over a - 1
B. 2a2 over a-1
C. 2a over a + 1
D. 2a over a-1
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5. Divide and simplify. 3x^3 over 4y divided x over 9

A. 27x over 4y^2
B. 27x over 4y^2
C. x^3 over 12
D. 27x^2 over 4

Answers

Answer 1
Answer:

Hi

(u²-4)/(u-6)(u-2)

= (u²-4)/(u²-8u+12)

= (u+2)(u-2)/(u-2)(u-6)

= u+2/u-6

The answer is A


5a³(2a)/ ab(35

= 10a^4/35ab

= 10a³/35b

= 2a³/7b

The answer is D


Sorry I don't understand the others. If you think this help is not enough please feel free to report it.


Please rate my answer.

Answer 2
Answer: The first one should be A since you can factor u^2-4 into (u+2)(u-2)

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Line AB is drawn from A(0,10) to B(-7,-4). Find point C that partitions line AB in ratio 5:2a) (-2,6)
b) (-3.5, 3)
c) (-5,0)
d) (-6,-2)

Answers

c) (-5, 0)

Working;
Use the formula;
x coordinate=( k_(1) x_(B)+ k_(2) x_(A) )/( k_(1) + k_(2) )( k_(1) y_(B) + k_(2) y_(A) )/( k_(1) + k_(2) )

The original value of a car is $18,000, and it depreciates (loses value) by 15% each year. what is the value of the car after three years?

Answers

If the original value of a car is $18,000, and it loses value by 15% each year, then you can calculate the new value of the car after n years using following formula:

P=\$18,000\cdot (1-0.15)^n.  

When n=3, then

P=\$18,000\cdot (1-0.15)^3=\$18,000\cdot 0.85^3=\$11,054.25.  

Answer: the value of the car after 3 years is $11,054.25.

I think the answer would be 11,054.25$


A small child makes 3 piles of blocks in a room. Each pile has 4 blocks. In another room, he makes 6 more piles of blocks. These piles also have 4 blocks each. To count the total number of blocks, his sister counts that there are 3 times 4, or 12 blocks, in one room and 6 times 4, or 24 blocks, in the other room for a total of 36 blocks. Using the distributive property, what is another way she could have counted the blocks?

Answers

4(3×6) is another way she could have counted them using distributive property which equals 36

The area of a rectangle is 5x^3+19x^2+6x-18 with length x + 3. Using synthetic division, what is the width of the rectangle?

Answers

To compute for the area of the rectangle, we multiply the dimensions so if  we need to find the width of the rectangle, we have

width = (Area)/(length)

Thus, given an area of (5x³ + 19x² + 6x - 18) and a length of (x + 3), to find the width, we have

width = (5x³ + 19x² + 6x - 18) / (x + 3)

Through the coefficients of the polynomial, we can apply synthetic division to find the quotient as shown below.

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   -15 -12  18
_____________
5   4   -6  0

Thus, the given values below the line are the coefficients of the width. So, we have the rectangle's width as (5x² + 4x - 6) units.

Answer: (5x² + 4x - 6) units

Answer:

A

Step-by-step explanation:

For edge

A man is five times as old as his son. Four years ago, he was nine times as old. Find their present ages.

Answers

Let us assume the age of the son now = x
Then
The age of the man now = 5x
Now we have to calculate the age of the son and father 9 years ago
Age of the son 4 years ago = x - 4
Age of the man 4 years ago = 5x - 4
Then
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- 4x = - 32
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  = 8
So the present age of the son is 8 years
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So the present age of the man is 40 years and the present age of the son is 8 years.

A restaurant sells tea for $1.50 plus 0.50 per refill. The restaurant brews enough tea for 4 refills per customer . The linear function that represents the total cost of rtea refills is C(r) = 0.5r + 1.5 . Describe an appropriate domain of this function . Make sure to identify the set of numbers appropriate to the domain

Answers

4.50Answer:

Step-by-step explanation:
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