Answer:
1st, 4th and 5th options are correct.
Step-by-step explanation:
Please find the attachment.
We are asked to choose three steps to calculate the volume of the given right triangular prism.
We know that base of triangular prism is triangle. The volume of triangular prism is area of base times height of the prism.
Let us find area of triangular base using area of triangle formula.
, where,
b = Base length,
h = Height of triangular base.
Therefore, 1st option is correct.
Upon substituting the base length (8 m) and height (14 m), we will get:
Therefore, 4th option is correct.
The volume of the prism would be area of base times height of prism (7 m) as:
Therefore, 5th option is correct as well.
Answer:
Step-by-step explanation:
Cancel the negative signs on both sides.
Evaluate.
Answer: -x-5
Step-by-step explanation:
-3x-15 . Both 3 and 15 are variables of 3, this means they can both be divided by 3. -3/3= -1 and -15/3=-5. So -1x-5, or -x-5
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Answer:
11
Step-by-step explanation:
x^2+2
(3)^2+2
9+2=11
Answer:
Step-by-step explanation:
A quadratic equation in one variable given by the general expression:
Where:
The roots of this equation can be found using the quadratic formula, which is given by:
So:
As you can see, in this case:
Using the quadratic formula:
Therefore, the answer is:
18 ÷ 12
B
12 ÷ 18
C
12 x 18
D
12 x 12 x 18
Answer:
B
Step-by-step explanation:
The rectangular coordinate of the given polarcoordinate will be (- 3.5,6.062).
A pair of numbers that employ the horizontal and vertical distinctions from the two reference axes to represent a point's placement on a coordinate plane. typically expressed by the x-value and y-value pairs (x,y).
Coordinates are always written in the form of small brackets the first term will be x and the second term will be y.
As per the given polar coordinates,
(7, 2π/3)
It is known that, x = r cosθ and y = r sinθ.
x = 7 cos(2π/3) and y = 7 sin(2π/3)
x = -3.5 and y = 6.062
Hence "The rectangular coordinate of the given polarcoordinate will be (- 3.5,6.062)".
For more about coordinates,
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