If 105 J of energy is used in 103 s, what is the average power consumption in watts?

Answers

Answer 1
Answer: Power = work/time

P = 105J/103s

P = 1.019 watts

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Who speaks the line "Lord, what fools these mortals be"? A. Oberon
B. Cobweb
C. Mustardseed
D. Puck

Answers

The answer is D.Puck.

♡♡Hope I helped!!! :)♡♡

What is the best classification for this sample of crude oil?

Answers

Most oil classification experts will tell you that you've got to see it,
smell it, weigh it, and feel it before you can classify it.  The absolute
minimum is to SEE it, or else have somebody describe it to you. 
At the moment, we are totally bereft of any information regarding
your sample, so we're in no position to classify it.  We can't even
be sure that you really DO have a sample of crude there.  For all
we know, you may be just joshin', waiting to see if we'll take the bait.
mixture of different hydrocarbons

Which of the following activities would have the highest excessive momentum?a. golf
b. gymnastics
c. tennis
d. wrestling

Answers

Either B. or C. I am pretty sure it is B.

Answer:

B

Explanation:

The answer is b. gymnastics

How do you find the pressure (in physics) if you are given the force (Newtons) and how far the object sunk into the ground?

Answers

Answer:

pressure=force/area

Explanation:

pressure equal to force divided by area,the area is how far the object sunk into the ground

A spring gains 2.34 joules of elastic potentialenergy as it is compressed 0.250 meter from its
equilibrium position. What is the spring constant
of this spring?
(1) 9.36 N/m (3) 37.4 N/m
(2) 18.7 N/m (4) 74.9 N/m

Answers

The correct answer to the question is: 4) 74.9 N/m.

EXPLANATION:

As per the question, the stretched length of the spring is given as x = 0.250 m.

The potential energy gained by the spring is given as 2.34 joules.

We are asked to calculate the spring constant of the spring.

The potential energy gained by the spring is nothing else than the elastic potential energy .

The elastic potential energy of the spring is calculated as -

               Potential energy P.E = (1)/(2)kx^2

                                            ⇒k = (2P.E)/(x^2)

                                                  = (2* 2.34)/((0.250)^2)\ N/m

                                                  = 74.88 N/m

                                                  = 74.9 N/m.                  [ans]

Hence, the force constant of the spring is 74.9 N/m.


Elastic energy equals 1/2 k(spring constant) *Δx^2(change in position) so you set the energy of the spring equal to the 1/2kΔx^2 and solve for K. 2.34=1/2k(.250)^2 which gives you a spring constant of 74.9 N/m.

Part 1. A girl leaves a history classroom and walks 10 meters north to a drinking fountain. Then she turns and walks 30 meters south to an art classroom. What is the girl's total distance traveled? Part 2. Using the information above from Part 1. What is the girl's total displacement from the history classroom to the art classroom?

Answers

The total distance traveled by the girl will be 40 meters and the displacement will be 30 meters.

What will be the distance and displacement of the girl?

Distance = total amount of path followed by any body called distance.

Displacement= The minimum distance between two points irrespective to the path followed by the body is displacement.

It is given that

Distance traveled to north direction = 10 metres

Distance traveled to south direction= 30 metres

So the path followed by the girl in total = North direction + south direction

                                                                 = 10+30

                                                                 = 40 meters

And the displacement  = min distance between History class and fountain

                                      = 30 meters

total distance traveled by the girl will be 40 meters and the displacement will be 30 meters.

To learn more about Distance and Displacement follow

brainly.com/question/127432

She walks/travels 40 meters. Her displacement is 20 metres because she walked 10m, back those same 10m and the 20m to the art classroom.