12x + 7y = 218
The first equation can be multiplied by –13 and the second equation by 7 to eliminate y.
The first equation can be multiplied by 7 and the second equation by 13 to eliminate y.
The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.
Answer:
The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
Answer: Fraction of the estate Debra will received is
Step-by-step explanation:
Since we have given that
Amount shared by Debra and Lan = $1000,000
Amount received by Lan = $125,000
According to question, Debra received the rest.
So, Amount received by Debra is given by
Fraction of the estate Debra will receive is given by
Hence, Fraction of the estate Debra will received is
n = −3
n = fraction 3 over 4
n = fraction 1 over 4
Answer:
n=1
Step-by-step explanation:
Answer:
.
Step-by-step explanation:
Given : phrase the quotient of 3 and z.
To find :what is the algebraic expression for the following word phrase .
Solution : We have given
Phrase the quotient of 3 and z.
We get the quotient when we divide the two terms.
So , We need to divide 3 and z to get the quotient.
Quotient = .
Therefore, .
The algebraicexpression for the word phrase "the quotient of 3 and z" is 3/z or 3 ÷ z.
We have,
The word "quotient" indicates division, so we know that we need to perform a division operation.
In this case, we are dividing the number 3 by the variable z.
In algebraic notation, the division is typically represented using the forward-slash (/) or the division symbol (÷).
Therefore, we can write "the quotient of 3 and z" as 3/z or 3 ÷ z.
Both expressions convey the idea that we are dividing 3 by the value of z.
Thus,
The algebraicexpression for the word phrase "the quotient of 3 and z" is 3/z or 3 ÷ z.
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Answer: Here's my answer
Step-by-step explanation:
The relationship given, 27, is neither linear nor exponential.
In a linear relationship, the dependent variable (y) changes at a constant rate for every unit increase in the independent variable (x). This results in a straight line when plotted on a graph. However, the given value, 27, does not provide any information about how the variable changes in relation to another variable. Without this information, we cannot determine if the relationship is linear.
In an exponential relationship, the dependent variable (y) changes at an increasing or decreasing rate based on a constant ratio for every unit increase in the independent variable (x). This results in a curved line when plotted on a graph. Since the given value, 27, does not provide any information about the rate of change or the constant ratio, we cannot determine if the relationship is exponential.
Therefore, based on the given information, the relationship 27 is neither linear nor exponential.