MATHEMATICS HIGH SCHOOL

Simplify 3 square root of 10 end root plus 7 square root of 15 end root minus 6 square root of 10 end root minus 4 square root of 15.3 square root of 10 end root minus 3 square root of 15
3 square root of 15 end root minus 3 square root of 10
3 square root of 30 end root minus 3 square root of 20
3 square root of 20 end root minus 3 square root of 30

Answers

Answer 1
Answer: 3√10 + 7√15 - 6√10 - 4√15
3√10 - 6√10 + 7√15 - 4√15
-3√10 + 3√15

The answer is B.
Answer 2
Answer:

Answer:

b

Step-by-step explanation:

Related Questions

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Find the slope of the line between y = 1/8x -1
Solve the linear equation: 3.4 + 2(9.7 – 4.8x) = 61.2 What are the possible steps involved in solving this equation? Check all that apply.
PLEASE HELP ME GUYS?!Please show me steps to solve.
The term "precision" BEST refers to which of the following?a. whether or not a measurement is correctb. how "close together" a set of measurements isc. whether or not a tool for making measurements is usefuld. how close a measurement is to an accepted value for the measurement

Which of the following statements is true?10 x 7/2

The product will be less than 10.
The product will be greater than 10.
The product will be equal to 10.

Answers

the product would be greater cuz ur dividing 7 by 2 witch is 3.5 then multiplying that by 10 witch would be 35

Line AB contains points A (1, 2) and B (−2, 6) The slope of line AB is a)zero
b)undefined
c)positive
d)negative


The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?
Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is
Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (−2, 2). Lines QR and ST are
The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).
The equation of line CD is y = −2x − 2. Write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5).

Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (−2, 2). Lines QR and ST are

parallel because the product of the slopes is −1

perpendicular because the product of the slopes is −1

parallel because the slopes are the same

perpendicular because the slopes are the same



Question 2

(06.02 LC)

The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?

1 over 2

2

negative 1 over 2

−2



Question 3

(06.02 LC)

Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is

zero

undefined

positive

negative



Question 4

(06.02 MC)

The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).

y = 2x + 16

y = negative 1 over 2x + 17 over 2

y = − 1 over 2x + 7 over 2

y = 2x − 4



Question 5

(06.02 MC)

The equation of line CD is y = −2x − 2. Write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5).

y = −2x + 13

y = negative 1 over 2x + 7

y = 1 over 2x + 3

y = − 2x − 3

Answers

On the first question, the formula would be  m=\frac{y2-y1}{x2-x1} and the value we got is -4/3, so D.
On the second quesiton, the slope in the given equation of the line is -2, its negative reciprocal is 1/2, so A.
On the third question, use the slope formula above and the value you would get is zero, so A.
On the fourth question, the equation of the line perpendicular to line QR is y=2x+b, to find b, just substitute the point (5,6) to the equation. That would make b = -4. the final equation of the line would be: y=2x-4, so D.
On the fifth question, the equation of the line parallel to line QR is y = -2x + b. substitute the point (4,5) to the equation, and you'll get b = 13. the final equation of the line would be y=-2x+13, so A.

Answer:

the answers to all of the questions are D,A,A,D,A

Step-by-step explanation:

What is the exact area of a circle whose diameter is 14 cm?A.
14 straight pi cm2

B.
28 straight pi cm2

C.
49 straight pi cm2

D.
196 straight pi cm2

Answers

Ok so the formula for the area of a circle is pi r2 so first the radius half of 14 is 7 so 7 squared would be 49 so it would be C. and if you wanted to get the estimation you would just multiply pi to 49 I hope this helps :) 

If the probability that the Seahawks will win any given game is 0.6, the probability that they will lose three games in a row is _? Write your answer as a decimal.

Answers

-- If the probability of winning any given game is 0.6,
then the probability of losing that game is 0.4 .

The probability of losing Game #1  =  0.4 
The probability of losing Game #2  =  0.4
The probability of losing Game #3  =  0.4

The probability of all 3 events occurring  =  (0.4) · (0.4) · (0.4)

                                                           =  (0.064)  =  6.4% . 


Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(-1, 1) and Q(5,9)

Answers

The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
((x_1+x_2)/(2), (y_1+y_2)/(2))
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

P(-1,1) \nx_1=-1 \n y_1=1 \n \n Q(5,9) \n x_2=5 \n y_2=9 \n \n(x_1+x_2)/(2)=(-1+5)/(2)=(4)/(2)=2 \n (y_1+y_2)/(2)=(1+9)/(2)=(10)/(2)=5

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
d=√((x_2-x_1)^2+(y_2-y_1)^2)

(-1,1) \n x_1=-1 \n y_1=1 \n \n (2,5) \n x_2=2 \n y_2=5 \n \n d=√((2-(-1))^2+(5-1)^2)=√(3^2+4^2)=√(9+16)=√(25)=5

The radius is 5.

(x-2)^2+(y-5)^2=5^2 \n\boxed{(x-2)^2+(y-5)^2=25}

7x - 3y = 4 2x - 4y = 1 Which of the following system of equations is not equal to the system of equations shown above?

Answers

This is the system given by you: a) 7x - 3y = 4 and b) 2x - 4y = 1

I will compare it with these three systems:

1) -28x + 12 = -16 and 28x - 56y = 14

You can check that if you mulitply the equation a) times - 4 and the equation b) times  -14, you get the equations of this new system. Then the two systems are equal.

2)  28x  - 12y = 16 and -6x + 12y = - 3

You can check that if you multiply the equation a) times 4 and the equation b) times - 3 you get the same equations of this system, then the two systems are equals.

3) 14x - 6y = 4 and -14x + 28y = 1

You can check that these equations cannot not be obtained from a) and b) then the systems are different.

You can solve both systems and you will obtaind different values for the xs and the ys.
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