b. 8,000 × 50
c. 120 × 300
2. Fill in the missing factors to find the given estimated product. The first one is done for you.
a. 582 x 23 ≈ __600________ x ___20_______ = 12,000
b. 325 x 454 ≈ __________ x __________ = 150,000
c. 6,397 x 349 ≈ __________ x __________ = 1,800,000
3. Round the factors and estimate the products. Round to the highest place value.
a. 656 × 106 ≈ __________ x __________ = __________
b. 3,108 × 7,942 ≈ __________ x __________ = __________
c. 425 × 9,311 ≈ __________ x __________ = __________
of the remaining children get off, leaving the bus only half full.
How many children were on the bus at the start?
Answer:
12
Step-by-step explanation:
If there are x children on the bus at the start, after the first stop, there are (x-3) remaining. After two stops, the number on the bus is ...
x/2 = x -3 -(1/3)(x -3)
Multiplying by 6, we have ...
3x = 6x -18 -2(x -3)
3x = 4x -12 . . . . simplify
12 = x . . . . . . . . add 12-3x
There were 12 children on the bus at the start.
_____
Check
After 3 got off at the first stop, there were 12-3 = 9 remaining. 1/3 of those, or 9/3=3 got off at the second stop, so 9 -3 = 6 remained. This is half the original number, as required.
Let X represent the number of children on the bus originally. The equation formed is 2/3*(X - 3) = X/2, and when we solve it, we find that X equals 12 which indicates that there were 12 children on the bus at the start.
Let's denote the number of children on the bus at the start as X. After the first stop, the number of children on the bus became X - 3, because 3 children got off. After the second stop, a third of the remaining children got off, so the number of children on the bus became 2/3*(X - 3). According to the problem, after all the stops, the bus was half full. Therefore, we can set up an equation: 2/3*(X - 3) = X/2.
To solve the equation, we can multiply all terms by 6 to clear out the fractions and obtain the equation: 4*(X - 3) = 3X. This simplifies to 4X - 12 = 3X which simplifies further to X = 12, meaning there were initially 12 children on the bus.
#SPJ3
Y=5/6 x+ 10
Based on the line of best fit, if an employee works at a company for six years, how much vacation time will he or she accrue?
A.
20 days
B.
15 days
C.
13 days
D.
6 days
37 and 38
consecutive integers have a difference of 1 between them
let n and n + 1 be the consecutive integers, then
n + n + 1 = 75 ( subtract 1 from both sides )
2n = 74 ( divide both sides by 2 )
n = = 37
the integers are 37 and 37 + 1 = 38