What can a doctor use to determine a patient's body fat percentage?Bioelectrical impedance machine
MRI machine
Waist measurement
Weight measurement

Answers

Answer 1
Answer:

It is Bioelectrical impedance machine, these devices are used to measure the percentage of fat on your body so it is B

Answer 2
Answer:

Bioelectrical impedance machine

That is definitely the answer, so A not B


Related Questions

The graph of which function has an axis of symmetry at x =-1/4 ?f(x) = 2x2 + x – 1 f(x) = 2x2 – x + 1 f(x) = x2 + 2x – 1 f(x) = x2 – 2x + 1
What rational number could be graphed between 0 and 1?
Solve the system of equations. 2x − 5y = 3 x − 3y = 1 (4, 1) (5, 2) (7, 2) (9, 3)
40,43,40,39,50,23 what is the median?
!!!!!!!!50 POINTS!!!!!!!!!!!!Suppose a square has a side length by the expression x+5/8x. What is the perimeter of the square?

Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?f(x) = –x2 – 8x – 16

f(x) = –x2 + 8x – 16

f(x) = –x2 – 8x + 16

f(x) = –x2 + 8x + 16

Answers

Hello,

f(x)=-(x-4)²=-(x²-8x+16)=-x²+8x-16

Answer B

Answer:

The answer is B. Just took the test.

Step-by-step explanation:

Find the distance between (-1, 4) and (3, 1).

Answers

The Distance is 5, I believe 


4, -3 is the answer to Distance 

50 is 6.25% of what number?

Answers

Answer:

800

Step-by-step explanation:

Answer:

i think its 800

Step-by-step explanation:

taking the test

What is the square root of ab??
ab
O b squareroot a
2²6²
0 B²

Answers

Answer:

The choice 2.

b √(a)

Step-by-step explanation:

\sqrt{a {b}^(2) } = √(a) * \sqrt{ {b}^(2) } = √(a) * b \n \n = b √(a)

The difference between the highest and lowest single game point totals for the MIDDLE HALF of the data is ______ points less for Joe's data than Sam's data. Therefore, the MIDDLE HALF of Joe's single game point totals are less varied than Sam's.

Answers

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required data to answer the question are missing.

However, the interpretation of the question is to determine the interquartile range (IQR) of a certain dataset.

Then get the difference between the calculated IQR & Joe's data and also the difference between the calculated IQR & Sam's data

Then, make comparison

To do this, I will use the following assumed datasets.

Data: 62, 63, 64, 64, 70, 72, 76, 77, 81, 81

IQR is calculated as:

IQR = Q_3 - Q_1

Q_3 is the\ median of the upper half

Q_1 is the\ median of the lower half

For Joe, we have:

Lower\ half: 62, 63, 64, 64, 70

Upper\ half: 72, 76, 77, 81, 81

The median is then calculated as:

M = (N + 1)/(2)

For, the lower half:

Q_1 = (5 + 1)/(2) = (6)/(2) = 3rd

So:

Q_1 = 64

For the upper half:

Q_3 = (5 + 1)/(2) = (6)/(2) = 3rd

So:

Q_3 = 77

When the same process is applied to Sam's data,

Q_1 = 52

Q_3 = 58

IQR = Q_3 - Q_1

IQR = 77 - 64

IQR = 13

Assume that:

Joe = 60

Sam = 65

Joe - IQR = 60 - 13 = 47

Sam- IQR = 65- 13 = 52

Hence, the IQR is 47 points less for Joe's data than Sam's

A jar lid has a diameter of 42 millimeters.What is the circumference of the lid?

Answers

\sf{Circumference = \pi * diameter

We are given that the diameter = 42 millimeters

C = \pi * 42\n\n\boxed{\bf{C = 42\pi \approx 131.95~mm}}

The circumference of the lid is approximately 131.95 millimeters.
circumference of a circle = π x diameter

= π x 42
131.946891451
= 132 mm