What is the y-intercept of the graph of y= -4x^2+8x-3?
-3
2
1
-4

Answers

Answer 1
Answer: Hello,

-4x²+8x-3=0
==>4x²-8x+3=0
Δ=8²-4*3*4=64-48=16
==>(x=(8-4)/2=2) or (x=(8+4)/2=6)

Answer B: 2

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At 8:00 am, a building casts a shadow 75 feet long. The angle where the ray from the sun met the ground is 50°. How tall is the building?

Answers

the angle of elevation of shadow from building is 50 degrees
tan 50=height of building/length of shadow=h/75
h=75tan50=75(1.192)=89.38 feet
the height of the building is 89.38 feet

The rational and the irrational numbers together are called whole numbers. true or false

Answers

the answer is false

Step-by-step explanation:

natural numbers and zero are whole numbers

The answer is false

Since 1950, the growth in the world population in millions closely fits the exponential function A(t) = 26000.018t, where t is the number of years since 1950. Estimate the population in the year 2018 to the nearest million.​

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Step-by-step explanation:

Can u please get help with this Question?

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the answer is positive 0.25

How do you construct congruent segments, segment bisectors, angles, and angle bisectors using tools such as a compass and straightedge?

Answers

The compass is used for making circles I'm which you can later measure the length of the diameter and radius afterwards. With a ruler. To make segments, angles, and etc. You should use a vertex marker.

Final answer:

We can construct congruent segments, segment bisectors, equal angles and angle bisectors using tools like a straightedge and compass. Using arc intersections and connecting them with straight lines help us in achieving most of these. The important thing is to understand the right points from where to make the arcs originating.

Explanation:

To construct congruent segments, simply measure the length of the initial segment with your compass, then use the compass to draw another segment of the same length.

To create a segment bisector, use a compass to draw two arcs with the same radius from the segment's endpoints and then connect their intersection points with a straight line. This will create a line that bisects, or divides, the original segment into two congruent parts.

For equalling angles, first construct the initial angle using a straightedge and compass. Then place the point of the compass at the vertex of the angle, draw an arc through the sides, and repeat this process to copy the angle.

To create an angle bisector, draw an arc centered at the vertex of the angle. Then, from the points of intersection of the arc with the angle, draw two additional arcs within the angle that intersect with each other. Draw a straight line from the vertex to the point of intersection of these arcs.

Learn more about Geometrical Constructions here:

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a teacher needs 70 lengths of string cut to 40 cm each. If balls of string are 10 m long how many balls will be needed

Answers

The balls need for the given question is 28.

Given-

Total required string is 70.

The length of the required string is 40 cm.

The length of the ball of string is 10 m.

Convert the length of ball in centimetre from meter. We know that one meter has hundredcentimetres. Thus ten meters is,

=10* 100

=1000

Hence the length of the ball of string is 1000 cm.

Now the string is cut thus we need two lengths of string. Therefore,

=40* 2

=80

Two length of string is 80 cm.

Now this is the half times the lengths of the seventy. Thus,

=(70)/(2) *{80}

=2800

For this 2800 cm string we need 1000 cm string ballsn are,

n=(2800)/(1000)

n=28

Hence, the balls need for the given question is 28.

For more about the units follow the link below-

brainly.com/question/15602440

A meter is 100 cm. A ball of string has 10m of string, and you multiply 10m by 100cm, you get 1,000cm. Then you multiply 40cm by 2, and you get 80cm, or two lengths of string. Then you multiply 35, which is half of 70, by 80, and that is 2,800 cm.
2,800
÷40cm=70
And 100cm=1m.
The teacher will therefore need 28 balls of string.