Answer:
The exact probability = 0.0431
Step-by-step explanation:
Given: A bag contain - Caramels= 12, mints= 12, bars of dark chocolates= 14
Marilyn picks three items from the bag without replacement.
Total number of items 12+12+14=36
Now, probability = favorable outcome / total no. of outcomes
Probability of picking a mint =
After picking a mint there are :
caramels=10, mints=11, bars of chocolate=14
Total items in the bag=35
Probability of picking another mint =
now, caramels=10, mints=10, bars of chocolate=14
Total items in the bag=34
Probability of picking a bar of dark chocolate =
The exact probability of picking the items:
Therefore, the exact probability = 0.0431
Answer:
∠ GFH = 55°
Step-by-step explanation:
∠ GFH and ∠ GFE are a linear pair and sum to 180° , that is
∠ GFH + ∠ GFE = 180°
∠ GFH + 125° = 180° ( subtract 125° from both sides )
∠ GFH = 55°
–12p2– 12pq + 2p – 3q2 + q
–9p2q2 + 12pq – 2p + q
12p2 + 12pq +2p + 3q2 + q
The product of the 2p + q and –3q – 6p + 1 is .
Given
The given terms are;
2p + q and –3q – 6p + 1
To find a product, you'll need to multiply at least two numbers together following all the steps given below.
The product of the terms is;
Hence, the product of the 2p + q and –3q – 6p + 1 is .
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Answer: Second option is correct.
Step-by-step explanation:
Since we have given that
We need to product the two polynomials .
Here it is :
Hence, Second option is correct.
A. 3(J + 15) = J - 1
B. J + 15 = 3J - 1
C. J + 15 = 3(J - 1)
If J represents John's age, then J + 15 = 3(J - 1) equations could be used to solve the problem
Two or more expressions with an equal sign is called as Equation.
Given that
"I am 3 times as old as Sue is," Frank said to Ann. "On the other hand, I am 15 years older than John while Sue is 1 year younger than John.
F=Frank
J=John
S=Sue.
I am 15 years older than John
In the sense Frankes age is 15 more than John age, So it is 15+J
Sue is 1 year younger than John.
So Sue's age is less than john
J-1
"I am 3 times as old as Sue is"
Three times of J-1
3(J-1)
So equating this we get
Frank's age is equal to three times Sue's age of John minus one, which is the left-hand side of our equation.
15+J=3(J-1)
Hence 15+J=3(J-1) is the equation could be used to solve the problem.
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Frank = F
Sue = S
John = J
F=3*S
F = J+15
S = J-1
If you want to find Frank's age, then his age would be equivalent to John's plus 15 years.
A.-Would not work because Frank is three times Sue's age, not John's (left hand side of the equation).
B.-Notice that the right hand side of the equation is equivalent to Sue's age, which we know is John-1, however it is currently written to be "three times Sue's age minus one" which would give us John's age, plus two more years than his actual age on the left hand side.
C.-Frank's age is equal to John's plus fifteen (right side of the equation) and Frank is equal to Sue's age times 3. But, if Sue is in terms of Johns, then Sue's age is John's minus one. Therefore, Frank's age is equal to three times Sue's age of John minus one, which is the left-hand side of our equation.
Therefore C is the answer. C:
Answer:
There is 120 milligrams of caffeine in a cup of coffee.
Step-by-step explanation:
A cup of brewed tea has 54 milligrams less caffeine than a cup of brewed coffee. A cup of tea has 66 milligrams of caffeine.
Let the amount of caffeine in a cup of coffee be = x
In the equation form, we can denote this as:
Solving for x
x = 120
Therefore, there is 120 milligrams of caffeine in a cup of coffee.
Answer:
First part is 8.
Second part is 9.
Step-by-step explanation:
Lucy wants to plant 16 roses, 24 sunflowers, and 32 lilies in her garden.
She wants to plant only one type of flower in each row, and she wants each row to have the same number of plants.
We will take the greatest common factor of 16, 24 and 32
16 = 2 x 2 x 2 x 2
24 = 2 x 2 x 2 x 3
32 = 2 x 2 x 2 x 2 x 2
Now the greatest common factor is = 2 x 2 x 2 = 8
Therefore, the maximum number of flowers she can plant in each row is 8.
All flowers are =
If she plants the maximum number of flowers in each row and uses all of the flowers, she can plant rows of flowers.
Or we can also find this by :
Totaling these we get = rows.
8 and 9
.........................................................................
A 8 can go into 66 eight times, with a remainder of 2.
To calculate how many times 8 can go into 66, we need to perform long division.
Step 1: Set up the long division:
8 | 66
Step 2: Determine how many times 8 can go into the first digit of 66 (which is 6). It goes 8 times (8 x 8 = 64). Write 8 above the division bar.
8 | 66
8
Step 3: Subtract 64 from 66 to get the remainder. Bring down the next digit (which is 6).
8 | 66
8
---
26
Step 4: Determine how many times 8 can go into 26. It goes 3 times (8 x 3 = 24). Write 3 above the division bar.
8 | 66
8
---
26
24
Step 5: Subtract 24 from 26 to get the remainder. There is no more digit to bring down, so the division is complete.
8 | 66
8
---
26
24
---
2
The final result is 8 times with a remainder of 2. Therefore, 8 can go into 66 eight times, with a remainder of 2.
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