MATHEMATICS HIGH SCHOOL

Evaluate b^2 c ^-1 for b = 8 and c = -4.

-16
1/16
16
256

Answers

Answer 1
Answer: Just plug in values:

(8)²·(-4)⁻¹ = 64 · 1/-4 = -16

So answer is -16.

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Answers

Answer:

Step-by-step explanation:

x > -9/5 or x < 17/5.

is your answer btw are you always that beutiful?

:)

Akar akar persaman 3x^2+x-4=0 adalah

Answers

factor (3x+4)(x-1)=0 so 3x+4=0 3x=-4 x=-4/3 x-1=0 x=1 x=1 and -4/3
1 and -4/3 ...........

Multiply (5x2 x − 4)(x 2). 5x3 x2 − 4x − 8 5x3 11x2 − 2x − 8 5x3 10x2 − 4x − 8 5x3 20x2 2x − 8

Answers

(5x^2 + x - 4)(x + 2) = x(5x^2 + x - 4) + 2(5x^2 + x - 4) = 5x^3 + x^2 - 4x + 10x^2 + 2x - 8 = 5x^3 + 11x^2 - 2x - 8

Answer:

5x^3 + 11x^2 - 2x - 8

Step-by-step explanation:

took the test hope this helps please mark brainlisets

A ratio is defined as:   A. a comparison between three sets.   B. a comparison between two sets.   C. a set of equal ratios.   D. two equal numbers.

Answers

A ratio is the quantitative relation between two amounts showing the number of times one value contains or is contained within the other. Therefore, the correct answer to the question "A ratio is defined as:" is "a comparison between two sets" (option B).

Cos A/1-tan A + sin A/1-cot A =sin A + cos A

Answers

(cosA)/( (cosA)/(cosA)- (sinA)/(cosA))+ (sinA)/( (sinA)/(sinA)- (cosA)/(sinA) )=sinA+cosA\n (cosA)/( (cosA-sinA)/(cosA)+ (sinA)/( (sinA-cosA)/(sinA) ) )=sinA+cosA\n ( cos^(2)A )/(cosA-sinA) }- (sin^(2)A )/(cosA-sinA)=sinA+cosA\n ( cos^(2)A-sin^(2)A )/(cosA-sinA)=sinA+cosA\ncos(2A)=(sinA+cosA)(cosA-sinA)\n cos(2A)=(sinA+cosA)(sinA-cosA)\ncos(2A)=sin^(2)A - cos^(2)A\ncos2A=cos2A \n1=1

Find the first 5 terms of the sequence: an = 4n-1.

Answers

#sol1

a1=1×4-1=3
a2=2×4-1=7
a3=3×4-1=11
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a5=5×5-1=19

#sol2

f(1)=1×4-1=3,
f(n+1)=f(n)+4,
so .... you know.
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