Answer:
-5/3 ft/sec
Step-by-step explanation:
In this question, we are asked to calculate the rate at which the height of the top of a ladder is changing given that the lower end is being dragged at a particular rate.
Please check attachment for complete solution and step by step explanation.
Answer:
The rate of change of height, dy / dt = -1.667 ft/s
Step-by-step explanation:
Solution:-
- The length of the ladder, L = 39 ft
- The foot of the ladder is moved away from wall at a rate, dx/dt = 4ft/s
Find:-
how fast is the height of the top changing (this will be a negative rate) when the lower end is 15 feet from the wall?
Solution:-
- We will first draw a right angle triangle, with vertical height of the ladder to be"y" and distance of the foot of the ladder and the wall to be "x".
- Then express the length "L" in terms of x and y using pythagorean theorem:
L^2 = x^2 + y^2
y^2 = 39^2 - x^2
- Taking height of the ladder as the dependent variable and distance of the foot of the ladder from wall as independent variable.
- Formulate a differential equation from the given expression above in terms of "dy/dt" and "dx/dt". Perform implicit differential of the computed expression "d/dt":
2y*dy/dt = -2x*dx/dt
dy / dt = -(x/y)*dx/dt
- Where, dy / dt : The change in height of the ladder.
- The height of the ladder at x = 15 ft is:
- Then evaluate dy/dt:
dy / dt = -(15/36)*4
dy / dt = -1.667 ft/s
1 0.06
2 0.20
3 0.48
4 0.26
Your question is incomplete. Please read below to find the missing content.
This score has a probability of 0.48, the highest of all four possible scores.
The answer is option 3.
Probability is virtually how possibly something is to happen. every time we're unsure approximately the final results of an occasion, we will speak about the probabilities of positive consequences—how possibly they are. The analysis of activities ruled by means of possibility is called statistics.
Learn more about Probability here: brainly.com/question/24756209
#SPJ2
ground 61 m horizontally from the point of
release.
What is the speed of the ball just before it
strikes the ground?
Answer in units of m/s
The speed of the ball would be 13 m/s just before it strikes the ground.
A ball is thrown horizontally from the top of a 110 m high building. 61 meters horizontally from the moment of release, the ball falls on the earth.
Velocity is defined as the displacement of the object in a given amount of time and is referred to as velocity.
First of all, we get the time of aviation from the vertical component:
Here s = 110 m and g = 9.8 m/s²
s = 1/2 × gt²
Solve for t
t = √(2s/g)
Substitute the values of s = 110 m and g = 9.8 m/s² in the equation,
t = √(2×110/9.8)
t = √22.44
t = 4.7 sec
The horizontal component of velocity is constant :
v = s/t
Here s = 61 m and t = 4.7 sec
v = 61/4.7
v = 12.97 ≈ 13
Therefore, the speed of the ball would be 13 m/s just before it strikes the ground.
Learn more about Velocity here:
#SPJ2
Answer:
what is math
Step-by-step explanation:
I want to teach you how to use a plane mirror to see if I want to go would have clear photo pathaununa is the best person like cmt thorai vyo
yeah a successful and non uniform and non-uniform is used for free a plane mirror a convex lens for Canon printer and non-uniform a successful and rich